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3 years ago

19. Arrange from smallest to largest: the BTU, the joule, and the calorie.

Physics

1 answer:

Papessa [141]3 years ago

5 0

Answer: Don't know sorry

Explanation:

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A simple harmonic oscillator consists of a block of mass 45 g attached to a spring of spring constant 240 N/m, oscillating on a

Brrunno [24]

Answer:

The maximum displacement ,A= 0.047 m

Explanation:

Given that

Mass, m = 45 g= 0.045 kg

spring constant ,K= 240 N/m

Initial velocity at equilibrium ,v= 3.5 m/s

Lets take the maximum displacement is A

As we know that when the mass reached at the extreme position then the velocity of the mass will become zero.

From energy conservation

$\dfrac{1}{2}KA^2=\dfrac{1}{2}mv^2$

$KA^2=mv^2$

$A=\sqrt{\dfrac{mv^2}{K}}$

Now by putting the values

$A=\sqrt{\dfrac{0.045\times 3.5^2}{240}}$

A=0.047 m

The maximum displacement ,A= 0.047 m

4 0

3 years ago

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Birds resting on high-voltage power lines are a common sight. the copper wire on which a bird stands is 1.28 cm in diameter and

nekit [7.7K]

Answer:

$8\cdot 10^{-4} V$

Explanation:

First of all, let's find the cross-sectional area of the copper wire. The radius of the wire half the diameter:

$r=\frac{d}{2}=\frac{1.28 cm}{2}=0.64 cm=6.4\cdot 10^{-3} m$

So the area is

$A=\pi r^2 = \pi (6.4\cdot 10^{-3} m)^2=1.29\cdot 10^{-4} m^2$

Now we can calculate the resistance of the piece of copper wire between the bird's feet, with the formula:

$R=\rho \frac{L}{A}$

where

$\rho=1.68\cdot 10^{-8} \Omega m$ is the resistivity of copper

$L=4.12 cm=4.12 \cdot 10^{-2} m$ is the length of the piece of wire

$A=1.29\cdot 10^{-4} m^2$ is the cross-sectional area

Substituting, we find

$R=(1.68\cdot 10^{-8} m^2)\frac{4.12\cdot 10^{-2} m}{1.29\cdot 10^{-4} m^2}=5.4\cdot 10^{-6} \Omega$

And since we know the current in the wire, I=149 A, we can now find the potential difference across the body of the bird, by using Ohm's law:

$V=IR=(149 A)(5.4\cdot 10^{-6} \Omega)=8\cdot 10^{-4} V$

4 0

3 years ago

A circuit has a voltage drop of 54.0 V across a 30.0 o resistor that carries a current of 1.80 A. What is the power used by the

Blizzard [7]

Answer:

P = 97.2 W

Explanation:

Given that,

Voltage drop, V = 54 V

The resistance of the resistor, R = 20 Ohms

Current, I = 1.8 A

We need to find the power used by the resistor. The formula used to find the power is given by :

P = VI

Putting all the values,

P = 54 V × 1.8 A

P = 97.2 W

So, the power used by the resistor is 97.2 W.

5 0

3 years ago

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2Mg+2HCI TO 2MgCI+2H2

motikmotik

2Mg + 2HCl →2MgCl + 2H₂

Balanced is:

4Mg + 4HCl → 4MgCl + 2H₂

I Hope I Helped

ΩΩΩΩΩΩΩΩΩΩ

6 0

3 years ago

What is the mass of a cylinder of lead that is 1.80 in in diameter, and 4.12 in long. the density of lead is 11.4 g/ml?

Sedbober [7]

1950 g This is the answer due to the kilograms of lead being distributed

5 0

4 years ago

Read 2 more answers