Solution :
Speed of the air craft, = 262 m/s
Fuel burns at the rate of, = 3.92 kg/s
Rate at which the engine takes in air, = 85.9 kg/s
Speed of the exhaust gas that are ejected relative to the aircraft, =921 m/s
Therefore, the upward thrust of the jet engine is given by
F = 85.9(921 - 262) + (3.92 x 921)
= 4862635.79 + 3610.32
=
Therefore thrust of the jet engine is .
Answer:
(a). The value of d is 0.056 cm and 1.496 cm.
(b). The time period is 1.35 sec.
Explanation:
Given that,
Length = 50.00 cm
Time period = 2.50 s
Time period of pendulum is defined as the time for one complete cycle.
The period depends on the length of the pendulum.
Using formula of time period
Where, I = moment of inertia
We need to calculate the value of d
Using parallel theorem of moment of inertia
For a meter stick mass m , the rotational inertia about it's center of mass
Where, L = 1 m
Put the value into the formula of time period
Multiplying both sides by d
tex]T^2d=4\pi^2(\dfrac{L^2}{12g}+\dfrac{d^2}{g})[/tex]
Put the value of T, L and g into the formula
The value of d is 0.056 cm and 1.496 cm.
(b). Given that,
L = 50-5 = 45 cm
We need to calculate the time period
Using formula of period
Put the value into the formula
Hence, (a). The value of d is 0.056 cm and 1.496 cm.
(b). The time period is 1.35 sec.