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3 years ago

when it is time to end a reflux, first choose... and then turn off the heat. choose... until the system has cooled.

Chemistry

1 answer:

Zarrin [17]3 years ago

8 0

Answer:

second one is better

Explanation:

system is very much hot in first state..so wait for cooling down the system..but these depend on the organic compounds and products you are using. sometimes we need to carryout further steps in hot state..then you can't wail it to cool down

You might be interested in

Convert the following Grams: 0.200 moles of H2S

ANEK [815]

Answer:

6.82 g H₂S

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Atomic Structure

Reading a Periodic Table

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

0.200 mol H₂S

Step 2: Identify Conversions

Molar Mass of H - 1.01 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of H₂S - 2(1.01) + 32.07 = 34.09 g/mol

Step 3: Convert

Set up: $\displaystyle 0.200 \ mol \ H_2S(\frac{34.09 \ g \ H_2S}{1 \ mol \ H_2S})$
Multiply: $\displaystyle 6.818 \ g \ H_2S$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

6.818 g H₂S ≈ 6.82 g H₂S

7 0

3 years ago

what happens to the yield of hydrogen if the reaction is carried out at a higher temperature but at the same pressure

valkas [14]

Answer: It increases the rate of desulfurization at a constant feed rate

Explanation:

5 0

4 years ago

4Cuo - 2Cu,O + O, AH = 288 kJ

Anna35 [415]

I am a little slow i cannot help with these that why i got this app lol

6 0

3 years ago

What will be the theoretical yield of tungsten(is) ,W, if 45.0 g of WO3 combines as completely as possible with 1.50 g of H2

Anarel [89]

Answer:

35.6 g of W, is the theoretical yield

Explanation:

This is the reaction

WO₃ + 3H₂ → 3H₂O + W

Let's determine the limiting reactant:

Mass / molar mass = moles

45 g / 231.84 g/mol = 0.194 moles

1.50 g / 2 g/mol = 0.75 moles

Ratio is 1:3. 1 mol of tungsten(VI) oxide needs 3 moles of hydrogen to react.

Let's make rules of three:

1 mol of tungsten(VI) oxide needs 3 moles of H₂

Then 0.194 moles of tungsten(VI) oxide would need (0.194 .3) /1 = 0.582 moles (I have 0.75 moles of H₂, so the H₂ is my excess.. Then, the limiting is the tungsten(VI) oxide)

3 moles of H₂ need 1 mol of WO₃ to react

0.75 moles of H₂ would need (0.75 . 1)/3 = 0.25 moles

It's ok. I do not have enough WO₃.

Finally, the ratio is 1:1 (WO₃ - W), so 0.194 moles of WO₃ will produce the same amount of W.

Let's convert the moles to mass (molar mass . mol)

0.194 mol . 183.84 g/mol = 35.6 g

3 0

3 years ago

Tony made 14L of lemonade for a party. His guests drank 9500mL of the lemonade. How many milliliters did Tony have left?

Anuta_ua [19.1K]

Since 9500 mL of lemonade equals 9.5 liters, that means that Tony has 4.5 liters left, because 9.5 + 4.5 = 14

7 0

3 years ago