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Masja [62]
3 years ago
13

Two balloons are charged with an identical quantity and type of charge: 0.004 C. They are held apart at a separation distance of

5m. Determine the magnitude of the electrical force of repulsion between them.
Chemistry
1 answer:
lukranit [14]3 years ago
6 0

Answer:

The answer to your question is F = 28800 N

Explanation:

Data

q₁ = q₂ = 0.004 C

distance = r = 5 m

k = 9x 10⁹ C

Force = F

Formula

F = k q₁ q₂ / r²

-Substitution

F = (9 x 10⁹)(0.004)(0.004) / (5)²

-Simplification

F = 144000 / 25

-Result

F = 28800 N

-Conclusion

The force of repulsion between these balloons is 28800 N

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calculate the mass of 120cc nitrogen present at STP. how many number of molecules are present in it?​
Stells [14]

Answer:

0.15008\ \text{g}

3.23\times 10^{21}

Explanation:

1 mol of nitrogen at STP = 22.4 L = 22400 cc

n = Mol of N_2 = \dfrac{120}{22400}=0.00536\ \text{mol}

M = Molar mass of N_2 = 28\ \text{g/mol}

N_A = Avogadro's number = 6.022\times 10^{23}\ \text{mol}^{-1}

Mass of N_2 is

m=nM\\\Rightarrow m=0.00536\times 28\\\Rightarrow m=0.15008\ \text{g}

Mass of the nitrogen is 0.15008\ \text{g}

Number of molecules is given by

nN_A=0.00536\times 6.022\times 10^{23}=3.23\times 10^{21}\ \text{molecules}

The number of molecules present in it are 3.23\times 10^{21}

5 0
3 years ago
This answer please :))
r-ruslan [8.4K]

Answer: ya this one

Explanation: this is the one

4 0
3 years ago
2. Perception:
sineoko [7]

Answer:

D

Explanation:

Someone's perception can be all of these things. the way one person sees something is different than the way someone standing right beside them sees it.

4 0
3 years ago
How many grams of Na2SO4 can be produced from 423.67 g of NaCl?
san4es73 [151]

Mass of  Na2SO4= 514.18 grams

<h3>Further explanation</h3>

Given

423.67 g of NaCl

Required

mass of  Na2SO4

Solution

Reaction

2NaCl + H2SO4 → Na2SO4 + 2HCl

mol NaCl :

= 423.67 g : 58.5 g/mol

= 7.24

From the equation, mol Na2SO4 :

= 1/2 x mol NaCl

= 1/2 x 7.24

= 3.62

Mass  Na2SO4 :

= 3.62 mol x 142,04 g/mol

= 514.18 grams

4 0
3 years ago
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Gnoma [55]
What volume of 2.50 m lead ll nitrato
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