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Masja [62]
3 years ago
13

Two balloons are charged with an identical quantity and type of charge: 0.004 C. They are held apart at a separation distance of

5m. Determine the magnitude of the electrical force of repulsion between them.
Chemistry
1 answer:
lukranit [14]3 years ago
6 0

Answer:

The answer to your question is F = 28800 N

Explanation:

Data

q₁ = q₂ = 0.004 C

distance = r = 5 m

k = 9x 10⁹ C

Force = F

Formula

F = k q₁ q₂ / r²

-Substitution

F = (9 x 10⁹)(0.004)(0.004) / (5)²

-Simplification

F = 144000 / 25

-Result

F = 28800 N

-Conclusion

The force of repulsion between these balloons is 28800 N

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Una muestra de 2,5000 (g) de piedra caliza, se disuelve y se precipita el Calcio como oxalato de Calcio (CaC2O4), este precipita
sergij07 [2.7K]

Answer:

\%Ca=19.378\%

Explanation:

¡Hola!

En este caso, basado en la información dada, es posible conocer la masa de calcio en carbonato de calcio, que de hecho es la misma en la muestra, al utilizar el siguiente esquema de cálculo:

m_{Ca}=1,2093gCaCO_3*\frac{1molCaCO_3}{100.1gCaCO_3}*\frac{1molCa}{1molCaCO_3}*\frac{40.1gCa}{1molCa}\\\\m_{Ca}=0.48444gCa

Finalmente, calculamos el porcentaje requerido como sigue:

\% Ca=\frac{0.48444g}{2.5000g} *100\%\\\\\%Ca=19.378\%

¡Saludos!

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