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3 years ago

Which experiment lead to the discovery that the tiny, dense nucleus contained most of

1 answer:

7 0

I think it was from los griegos but a long time a go because he was making and experiment with and apple and he notice that he couldn’t cut more so he name it atoms (sorry for my bad English I don’t speak English)

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Please help me

denis23 [38]

Consumption of a synthetic material being increased, leads to an associated negative impacts to Earth required to produce it is a True statement.

<h3>What is a Synthetic material?</h3>

There are the materials which are made by humans through chemical synthesis which are usually done in factories.

The production of this type of materials leads to the emission of chemicals and other gases which are harmful and negatively impacts the environment.

Read more about Synthetic material here brainly.com/question/24357817

8 0

2 years ago

Which of the changes of state shown in the model happen when thermal energy is added

AysviL [449]

Answer:

sublimation

Explanation:

immediately into a gas when thermal energy is added to it. The process is called sublimation. Sublimation is the change of state from a solid to a gas without going through the liquid state.

3 0

3 years ago

An oxybromate compound, kbrox, where x is unknown, is analyzed and found to contain 43.66 % br.

aniked [119]

Answer is: an oxybromate compound is KBrO₄ (x = 4).

ω(Br) = 43.66% ÷ 100%.

ω(Br) = 0.4366; mass percentage of bromine.

If we take 100 grams of compound:

m(Br) = ω(Br) · 100 g.

m(Br) = 0.4366 · 100 g.

m(Br) = 43.66 g; mass of bromine.

n(Br) = m(Br) ÷ M(Br).

n(Br) = 43.66 g ÷ 79.9 g/mol,

n(Br) = 0.55 mol; amoun of bromine.

From chemical formula (KBrOₓ), amount of potassium is equal to amount of bromine: n(Br) = n(K).

m(K) = 0.55 mol · 39.1 g/mol.

m(K) = 21.365 g; mass of potassium in the compound.

m(O) = 100 g - 21.365 g - 43.66 g.

m(O) =34.97 g; mass of oxygen.

n(O) = 34.97 g ÷ 16 g/mol.

n(O) = 2.185 mol.

n(K) : n(Br) : n(O) = 0.55 mol : 0.55 mol : 2.185 mol /÷ 0.55 mol.

n(K) : n(Br) : n(O) = 1 : 1 : 4.

6 0

3 years ago

6. Cuando se oxidan en el aire 12,120 g de vapor de Zinc se obtienen 15,084 g del óxido. ¿Cuál es la fórmula empírica del óxido?

Eddi Din [679]

Answer:

12120 g + O2 = 15084 g

m Zn = 12.120 Kg

m óxido = 15.084 Kg

1. calcular la masa de cinc en gramos

g = 12,120 Kg x 1000 = 12120 g de cinc

g = 15.084 Kg x 100 = 15084 g de oxígeno

2. calcular gramos de Oxigeno

g O = 15084 g - 12120 g = 2964 g O2

3. calcular % de Zn y O

%m/m ( m soluto / m solc.) x 100

%m/m (Zn) = ( 1210 g / 15084 g ) x 100

% m/m (Zn) = 80.35 % = 80.35 g

%m/m (O) = ( 2964 g / 15084 g ) x 100

% m/m (Zn) = 19.65 % = 19.65 g

4. Calcular moles de cada elemento

Zn: 80.35 g / 65.38 g/mol = 1.228 mol

O: 19.65 g / 16 g/mol = 1.228 mol

5. dividir entre el menor de los elementos

Zn: 1.228 mol / 1.228 mol = 1

O: 1.228 mol / 1.228 mol = 1

6. Fórmula empírica: ZnO

3 0

3 years ago

What type of conspiracy did Apple take part in?

zimovet [89]

There is sufficient evidence to show that Apple violated Section 1 of Sherman Act by making publishers raise price of e-books.

Explanation:

Google

6 0

3 years ago

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