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3 years ago

what happens to the yield of hydrogen if the reaction is carried out at a higher temperature but at the same pressure

Chemistry

1 answer:

valkas [14]3 years ago

5 0

Answer: It increases the rate of desulfurization at a constant feed rate

Explanation:

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How do you convert 134kj to Calories?

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Electronegativities of the elements Be, Mg, Ca, and Sr follow a specific trend within their group. Based on this trend, the atom

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3 years ago

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12.<br> An object with a mass of 3 kg has a momentum of 75 kg•m/s. What is the velocity?

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Answer:

the velocity is 25 m/s

Explanation:

The computation of the velocity is shown below:

As we know that

Magnitude of Momentum = (mass) × (speed)

75 kg. m/s = 3 kg × speed

So, the speed is

= 75 ÷ 3

= 25 m/s

hence, the velocity is 25 m/s

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3 years ago

How many grams of lead(II) sulfate (303 g/mol) are needed to react with sodium chromate (162 g/mol) in order to produce 0.162 kg

Afina-wow [57]

Answer : The mass of $PbSO_4$ needed are, 1.515 grams.

Explanation :

First we have to calculate the mole of $PbCrO_4$ .

$\text{Moles of }PbCrO_4=\frac{\text{Mass of }PbCrO_4}{\text{Molar mass of }PbCrO_4}=\frac{0.162g}{323g/mole}=0.005mole$

Now we have to calculate the moles of $PbSO_4$ .

The balanced chemical reaction will be,

$PbSO_4+Na_2CrO_4\rightarrow PbCrO_4+Na_2SO_4[tex]From the balanced chemical reaction, we conclude thatAs, 1 mole of [tex]PbCrO_4$ produced from 1 mole of $PbSO_4$

So, 0.005 mole of $PbCrO_4$ produced from 0.005 mole of $PbSO_4$

Now we have to calculate the mass of $PbSO_4$

$\text{Mass of }PbSO_4=\text{Moles of }PbSO_4\times \text{Molar mass of }PbSO_4$

$\text{Mass of }PbSO_4=0.005mole\times 303g/mole=1.515g$

Therefore, the mass of $PbSO_4$ needed are, 1.515 grams.

6 0

3 years ago

what happens to the yield of hydrogen if the reaction is carried out at a higher temperature but at the same pressure​

what happens to the yield of hydrogen if the reaction is carried out at a higher temperature but at the same pressure