Answer:
a. n = 6,54 moles.
b. CH₃COOH(aq) + NaHCO₃(aq) → CH₃COONa(aq) + H₂O (l) + CO₂(g)
c. 549g of NaHCO₃
d. 7,85L of CH₃COOH
Explanation:
a. It is possible to know moles of CO₂ required to inflate the air bag using:
n = PV/RT
Where n are moles; P is pressure (1atm at room conditions); V is volume (160L); R is gas constant (0,082 atmL/molK); and T is temperature (298,15K at room conditions.
Replacing:
<em>n = 6,54 moles.</em>
b. The reaction of CH₃COOH with NaHCO₃ produce:
CH₃COOH(aq) + NaHCO₃(aq) → CH₃COONa(aq) + H₂O (l) + CO₂(g)
c. 1 mol of CO₂ is produced from 1 mol of NaHCO₃, that means 6,54moles of CO₂ are produced from <em>6,54 moles of NaHCO₃</em>. In grams:
6,54 moles NaHCO₃×
= <em>549g of NaHCO₃</em>
d. Again, you require 6,54 moles of CH₃COOH. If your acetic acid solution is 0,833M you need:
6,54moles×
= <em>7,85L of CH₃COOH</em>
<em></em>
I hope it helps!
Hello!
To solve this question, we need to use the
Avogadro's Number, which is a constant first discovered by
Amadeo Avogadro, an Italian scientist. He discovered that in a mole of a substance, there are
6,02*10²³ molecules. Using this relationship, we apply the following conversion factor:
So, 8,50 * 10²⁴ molecules of Na₂SO₃ represent
14,12 moles of Na₂SO₃
Have a nice day!
Cloud level (ft)Cloud type
High clouds (CH)
Base usually 20,000 ft or above, over British Isles
<span>CirrusCirrocumulusCirrostratus</span>
Medium clouds (CM)
Base usually between 6,500 and 20,000 ft over British Isles.
<span>AltocumulusAltostratusNimbostratus</span>
Low clouds (CL)
Base usually below 6,500 ft over British Isles.
hope this helps!
Answer:
double displacement reaction
A: It prevents most reactions from occurring spontaneously.
The answer above is correct.
