All categories

3 years ago

Counting by 8s Homework

Mathematics

1 answer:

galben [10]3 years ago

7 0

Answer:

8,16,24,32,40,48,56,64,72,80,88,96

Step-by-step explanation:

You might be interested in

In a triangle the base is 4 inches and the height is 6 inches. Find the area. Type a numerical answer in the space

MAVERICK [17]

Answer:

Step-by-step explanation:

area =1/2 base×height

=1/2 ×4×6

=12

8 0

3 years ago

How you write a inequality and then graph the answer?

Simora [160]

Answer:

To write an inequality, you need to write a number on the number line, and to graph it, you need to write another inequality and figure out what the answer is.

hope this helped.

3 0

2 years ago

SU and VT are chords that intersect at point R.

vovikov84 [41]

Answer:

<h2>The length of the line segment VT is 13 units.</h2>

Step-by-step explanation:

We know that SU and VT are chords. If the intersect at point R, we can define the following proportion

$\frac{RS}{RT} =\frac{RV}{RU}$

Where

$RS=SR=x+6\\RT=x+4\\VR=RV=x+1\\RU=x$

Replacing all these expressions, we have

$\frac{x+6}{x+4} =\frac{x+1}{x}$

Solving for $x$ , we have

$x(x+6)=(x+4)(x+1)\\x^{2} +6x=x^{2} +x+4x+4\\6x-5x=4\\x=4$

Now, notice that chord VT is form by the sum of RT and RV, so

$VT=VR+RT\\VT=x+1+x+4\\VT=2x+5$

Replacing the value of the variable

$VT=2(4)+5\\VT=8+5\\VT=13$

Therefore, the length of the line segment VT is 13 units.

5 0

3 years ago

Read 2 more answers

seven out of every 8 students surveyed owns a bike. The difference between the number of students who own a bike and those who d

guajiro [1.7K]

So if x people were surveyed, $\frac{7}{8}$ people owned a bike and $\frac{1}{8}$ did not.

The difference between them is 72:
$\frac{7}{8}$ x-\frac{1}{8} [/tex] =72
so this means that
$\frac{6}{8}$ x=72

let's simplify:

$\frac{3}{4}$ x=72

and divide by 3:

$\frac{1}{4}$ x=24

and mupliply by 4:

x=96

so 96 people were surveyed

5 0

3 years ago

) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle

Fynjy0 [20]

The surface (call it $S$ ) is a triangle with vertices at the points

$x=0,y=0\implies z=2\implies(0,0,2)$

$x=0,y=2\implies z=-2\implies(0,2,-2)$

$x=2,y=0\implies z=-8\implies(2,0,-8)$

Parameterize $S$ by

$\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=(20v,8v,4v)$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv$

$=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}$

8 0

4 years ago