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Bumek [7]
2 years ago
6

Simplify the expression: -2.3f+0.8f - 12-5

Mathematics
1 answer:
MaRussiya [10]2 years ago
8 0

Answer:

-1.5f - 17

Step-by-step explanation:

-2.3f + 0.8f - 12 - 5

= -1.5f - 17

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The ratio of the number of boys to the number of girls in a choir is 5 to 4. There are 60 girls in the choir. How many boys are
Ira Lisetskai [31]

Answer:

75

Step-by-step explanation:

for every 5 boys there are 4 girls

60 / 4 = 15

15 * 5 = 75

8 0
3 years ago
Here is an equation 2x + 9 = -15. What are three different equations that have the same solution as that equation? Show or expla
Sliva [168]

To find those equations we can do any multiplication or division of both sides of the equation:

Examples:

2x + 9 = -15              | · 2

4x + 18 = -30

2x + 9 = -15              | · (-1)

-2x - 9 = 15

2x + 9 = -15               | ÷ 2

x + 4.5 = -7.5

There is the same solution: x = -12.

6 0
3 years ago
Opal wanted to make some necklaces and sell them at a craft store. She made 37 necklaces and each necklace had somewhere between
alexandr402 [8]
<h3>The total number of beads used in making 37 necklaces is between 2,664 beads and 2,849 beads.</h3>

Step-by-step explanation:

Here, as given: The number of necklace made by Opal  = 37

The least number of bead used in each necklace  = 72

So, if each necklace is made using the least number of beads then,

The total number of beads  used in 37 necklace =  37 x ( beads in 1 necklace)

= 37 x  72  = 2,664 beads

So, the least number of total beads used in 37 necklaces  = 2,664 beads

The highest number of bead used in each necklace  = 77

So, if each necklace is made using the highest number of beads then,

The total number of beads  used in 37 necklace =  37 x ( beads in 1 necklace)

= 37 x  77  = 2,849 beads

So, if highest number of total beads used in 37 necklaces  = 2,849 beads

Hence, the total number of beads used in making 37 necklaces is between 2,664 beads and 2,849 beads.

5 0
3 years ago
JL is a diameter of circle k. If tangents to circle I are constructed through points L and K what relationships would exist betw
luda_lava [24]

i. Let t be the line tangent at point J. We know that a tangent line at a  point on a circle, is perpendicular to the diameter comprising that certain point. So t is perpendicular to JL
let l be the tangent line through L. Then l is perpendicular to JL ii. So t and l are 2 different lines, both perpendicular to line JL.
2 lines perpendicular to a third line, are parallel to each other, so the tangents t and l are parallel to each other.
Remark. Draw a picture to check the 
3 0
3 years ago
HELP!!!!!! I believe its B but I am not sure! :(
n200080 [17]

Answer:

A

Step-by-step explanation:

When solving for x as an exponent, we need to use logarithms in order to undo the operation and rearrange the terms. We use log rules to bring down the exponent and solve. Logarithms are the inverse operations to exponents and vice versa. We have one special kind of logarithm called the natural logarithm whose base is e. We write it as ln. Since our base is e here, we will use the natural logarithm to rearrange and isolate x.

e^{4x-1} =3

We begin by applying the natural logarithm to each side.

ln(e^{4x-1}) =ln(3)

Log rules allow use to rearrange the exponent as multiplication in front of the log.

(4x-1)ln(e) =ln(3)

ln e as an inverse simplifies to 1.

(4x-1)(1)=ln(3)

We now apply the inverse operations for subtraction and multiplication.

4x-1+1=1+ln(3)\\4x=1+ln(3)\\\frac{4x}{4} =\frac{1+ln3}{4} \\x =\frac{1+ln3}{4}

Option A is correct.

5 0
3 years ago
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