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Vesna [10]
3 years ago
6

Changing 25/4 fraction into a mixed fraction

Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
7 0
When you change it to a mix # it will be 6 1/4
Veronika [31]3 years ago
6 0
Divide 25 by 4 and you get 6 with a remainder of 1. That remainder of 1 can go over 4 to create the final answer of 6 and 1/4. 
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Find the surface area of the pyramid. DO THIS AS QUICK AS POSSIBLE
mrs_skeptik [129]

Explanation:

How many surface has a pyramid?

5 Faces

It has 5 Faces. The 4 Side Faces are Triangles. The Base is a Square.

8 0
2 years ago
David’s dog weighs p pounds. Owen’s dog weighs 30% more than David’s dog. How much does Owen’s god weigh?
tia_tia [17]

Answer:

30%p, are there answer choices?

Step-by-step explanation:

6 0
3 years ago
Let R be the region bounded by
loris [4]

a. The area of R is given by the integral

\displaystyle \int_1^2 (x + 6) - 7\sin\left(\dfrac{\pi x}2\right) \, dx + \int_2^{22/7} (x+6) - 7(x-2)^2 \, dx \approx 9.36

b. Use the shell method. Revolving R about the x-axis generates shells with height h=x+6-7\sin\left(\frac{\pi x}2\right) when 1\le x\le 2, and h=x+6-7(x-2)^2 when 2\le x\le\frac{22}7. With radius r=x, each shell of thickness \Delta x contributes a volume of 2\pi r h \Delta x, so that as the number of shells gets larger and their thickness gets smaller, the total sum of their volumes converges to the definite integral

\displaystyle 2\pi \int_1^2 x \left((x + 6) - 7\sin\left(\dfrac{\pi x}2\right)\right) \, dx + 2\pi \int_2^{22/7} x\left((x+6) - 7(x-2)^2\right) \, dx \approx 129.56

c. Use the washer method. Revolving R about the y-axis generates washers with outer radius r_{\rm out} = x+6, and inner radius r_{\rm in}=7\sin\left(\frac{\pi x}2\right) if 1\le x\le2 or r_{\rm in} = 7(x-2)^2 if 2\le x\le\frac{22}7. With thickness \Delta x, each washer has volume \pi (r_{\rm out}^2 - r_{\rm in}^2) \Delta x. As more and thinner washers get involved, the total volume converges to

\displaystyle \pi \int_1^2 (x+6)^2 - \left(7\sin\left(\frac{\pi x}2\right)\right)^2 \, dx + \pi \int_2^{22/7} (x+6)^2 - \left(7(x-2)^2\right)^2 \, dx \approx 304.16<em />

d. The side length of each square cross section is s=x+6 - 7\sin\left(\frac{\pi x}2\right) when 1\le x\le2, and s=x+6-7(x-2)^2 when 2\le x\le\frac{22}7. With thickness \Delta x, each cross section contributes a volume of s^2 \Delta x. More and thinner sections lead to a total volume of

\displaystyle \int_1^2 \left(x+6-7\sin\left(\frac{\pi x}2\right)\right)^2 \, dx + \int_2^{22/7} \left(x+6-7(x-2)^2\right) ^2\, dx \approx 56.70

7 0
1 year ago
The largest factor of 24 is
erastova [34]
The greatest common factor is six; The common factors are two and three
7 0
3 years ago
Read 2 more answers
Solve the following quadratic equation using the quadratic formula.
valentina_108 [34]
The quadratic formula tells you the solution to
  ax² +bx +c = 0
is
  x=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}
Plugging in the values a=5, b=-8, c=5, you get
  x=\frac{8 \pm \sqrt{(-8)^{2}-4\cdot 5\cdot 5}}{2\cdot 5} = \frac{8 \pm \sqrt{-36}}{10} = \frac{4 \pm 3i}{5}

Your solution is
  x=\frac{4-3i}{5},x=\frac{4+3i}{5}
8 0
3 years ago
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