Hey there! :)
To find an equation of a line that passes through (5, 1) and has a slope of 2, we'll need to plug our known variables into the slope-intercept equation.
Slope-intercept equation : y = mx + b ; where m=slope, b=y-intercept
Since we're already given the slope, all we really need to do is find the y-intercept.
We can do this by plugging our known values into the slope-intercept equation.
y = mx + b
Since we're trying to find "b," we need to plug in "y, m, x" into our formula.
(1) = (2)(5) + b
Simplify.
1 = 10 + b
Subtract 10 from both sides.
1 - 10 = b
Simplify.
-9 = b
So, our y-intercept is 9!
Now, we can very simply plug our known values into slope-intercept form.
y = mx + b
y = 2x - 9 → final answer
~Hope I helped!~
Answer:
k = 575
Step-by-step explanation:
let d be distance and h time.
Given d varies directly as h then the equation relating them is
d = kh ← k is the constant of variation
To find k use the condition d = 2875, h = 5, then
2875 = 5k ( divide both sides by 5 )
k = 575
Answer:
645 ÷ 50 = 12.9
I hope this helps and that you have a wonderful day ^‿^
Answer:
a₇₄ = - 209
Step-by-step explanation:
There is a common difference between consecutive terms , that is
79 - 83 = 75 - 79 = - 4
This indicates the sequence is arithmetic with nth term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 83 and d = - 4 , then
a₇₄ = 83 + (73 × - 4) = 83 + (- 292) = 83 - 292 = - 209
37=10+4.50x
x=number of students needed to make $37
37=10+4.50x
-10 -10
27=4.50x
/4.50 /4.50
6=x
She needs to 6 students to make $37 for an hour.
Hope it helps!
