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3 years ago

How much work is done when a force of 33 N pulls a wagon 13 meters?

Physics

1 answer:

kramer3 years ago

7 0

Answer:

Work = (force) x (distance)

Work = (33N) x (13m) = 429 N-m = 429 joules

IF the force is in exactly the same direction as the motion of the wagon.

Explanation:

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Assume that, when we walk, in addition to a fluctuating vertical force, we exert a periodic lateral force of amplitude 25 NN at

dexar [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Explanation:

From the question we are told

The amplitude of the lateral force is $F = 25 \ N$

The frequency is $f = 1 \ Hz$

The mass of the bridge per unit length is $\mu = 2000 \ kg /m$

The length of the central span is $d = 144 m$

The oscillation amplitude of the section considered at the time considered is $A = 75 \ mm = 0.075 \ m$

The time taken for the undriven oscillation to decay to $\frac{1}{e}$ of its original value is t = 6T

Generally the mass of the section considered is mathematically represented as

$m = \mu * d$

=> $m = 2000 * 144$

=> $m = 288000 \ kg$

Generally the oscillation amplitude of the section after a time period t is mathematically represented as

$A(t) = A_o e^{-\frac{bt}{2m} }$

Here b is the damping constant and the $A_o$ is the amplitude of the section when it was undriven

So from the question

$\frac{A_o}{e} = A_o e^{-\frac{b6T}{2m} }$

=> $\frac{1}{e} =e^{-\frac{b6T}{2m} }$

=> $e^{-1} =e^{-\frac{b6T}{2m} }$

=> $-\frac{3T b}{m} = -1$

=> $b = \frac{m}{3T}$

Generally the amplitude of the section considered is mathematically represented as

$A = \frac{n * F }{ b * 2 \pi }$

=> $A = \frac{n * F }{ \frac{m}{3T} * 2 \pi }$

=> $n = A * \frac{m}{3} * \frac{2\pi}{25}$

=> $n = 0.075 * \frac{288000}{3} * \frac{2* 3.142 }{25}$

=> $n = 1810 \ people$

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3 years ago

A person pushing a bin with 45 N of force slides the 3 kg plastic bin on a rough surface with friction. The plastic bin is movin

Firdavs [7]

Answer:

F = 0

Explanation:

Given that,

Force acting to push a bin = 45 N

Mass of the plastic bin, m = 3 kg

The plastic bin is moving with a constant velocity.

We need to find the net force acting on the box. Constant velocity means the change in velocity is equal to 0. It means acceleration will be 0.

As a result, the force acting on the box is equal to 0.

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3 years ago

When you swim in a pool, Select one: a. rolling friction occurs. b. fluid friction occurs. c. sliding friction occurs. d. static

Oduvanchick [21]

Answer:

b. fluid friction occurs

Explanation:

Water is a liquid and both going through air gas and liquid cause fluid friction.

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3 years ago

What is the first law of motion?

Misha Larkins [42]

Newton's first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

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3 years ago

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If a car travels at speed 10 m/s with an engine force of 2000 N, calculate the power of the car

STatiana [176]

Answer:

200N

Explanation:

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3 years ago