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polet [3.4K]
3 years ago
6

If a car travels at speed 10 m/s with an engine force of 2000 N, calculate the power of the car

Physics
1 answer:
STatiana [176]3 years ago
4 0

Answer:

200N

Explanation:

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Super cluster

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Which is developed during the process of technology design
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Explanation:

A(n) __________ is developed during the process of technological design.

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3 years ago
A 80 mW laser beam is polarized horizontally. It then passes through two polarizers. The axis of the first polarizer is oriented
inn [45]

The E(incident) for the first  polarizer is E(incident)=-76.1930384332

The E(incident) for the second  polarizer is E(incident)=12.340115991

<u>Explanation:</u>

<u>Solving the problem:</u>

<u>Given</u>

Transmitted data = 80 mW

First polarizer= 30 degree

Second polarizer= 60 degree

We have the formula,

E (transmitted) = E (incident)cos()

<u>1. Through the first polarizer</u>

E (transmitted) = E (incident)cos()

80=E(incident) cos(60 degree)     (according to law subtract the given degree with 90 degree).

Then,

E(incident)=E(transmitted) cos()

E(incident) =80×cos 60 degree

E(incident)=-76.1930384332

The E(incident) for the first  polarizer is E(incident)=-76.1930384332

<u>2. Through the first polarizer</u>

We have the formula,

E (transmitted) = E (incident)cos()

80=E(incident) cos(30 degree)     (according to law subtract the given degree with 90 degree).

Then,

E(incident)=E(transmitted) cos()

E(incident) =80×cos 30 degree

E(incident) =12.340115991

The E(incident) for the second  polarizer is E(incident)=12.340115991

<u></u>

4 0
3 years ago
When is the electric flux on a section of a closed surface positive?.
rodikova [14]
When the electric field pierces outward through the section.
5 0
2 years ago
A 2kg mass is moving at 3m/s. What is its kinetic energy?
Illusion [34]
<h2><u>KINETIC ENERGY</u></h2>

<h3>Problem:</h3>

» A 2kg mass is moving at 3m/s. What is its kinetic energy?

<h3>Answer:</h3>
  • \color{hotpink} \bold{9 \: J} \\

— — — — — — — — — —

<h3>Formula:</h3>

To calculate the velocity of a kinetic energy, we can use formula

  • \underline{ \boxed{  \tt KE =  \frac{1}{2} m{v}^{2}  } }

where,

  • v is the velocity in m/s
  • KE is the kinetic energy in J (joules)
  • m is the mass in kg

— — —

Based on the problem, the givens are:

  • KE (Kinetic energy) = ? (unknown)
  • m (mass) = 2 kg
  • v (velocity) = 3 m/s

<h3>Solution:</h3>

To get the velocity, substitute the givens in the formula above then solve.

\:   \: \tt KE =  \frac{1}{2} m{v}^{2}   \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \: \tt \:   KE =  \frac{1}{2} \times  2 \times {(3)}^{2}  \\ \tt  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  KE =  \frac{1}{2}  \times(2\times 9) \\ \tt  KE =  \underline{ \boxed{ \blue{ \tt9 \: J}}}

Therefore, the kinetic energy is 9 Joules.

3 0
2 years ago
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