Answer:
-1636cm
Step-by-step explanation:
We are required to determine how much longer the Giant Walking Stick is compared to the Rhinoceros Beetle and the Giant Weta Beetle combined.
Length of the Rhinoceros Beetle=1670cm
Length of the Giant Weta Beetle=53cm
Length of the Giant Walking Stick =87cm
This is based on the assumption that the lengths provided are accurate in that order.
Length of the Rhinoceros Beetle and the Giant Weta Beetle combined = 1670+53=1723cm
Difference with Length of Giant Walking Stick= 87-1723= -1636cm
Since our result is negative, the Giant Walking Stick is actually SHORTER than the length of the Rhinoceros Beetle and the Giant Weta Beetle combined.
Answer:
-14r + 6
Step-by-step explanation:
-12r + 6 - 2r
Answer:
i have autism and adhd and add and dmdd so plz dont yell at me that i did not answer it!!!
Step-by-step explanation:
To find the maximum or minimum value of a function, we can find the derivative of the function, set it equal to 0, and solve for the critical points.
H'(t) = -32t + 64
Now find the critical numbers:
-32t + 64 = 0
-32t = -64
t = 2 seconds
Since H(t) has a negative leading coefficient, we know that it opens downward. This means that the critical point is a maximum value rather than a minimum. If we weren't sure, we could check by plugging in a value for t slightly less and slighter greater than t=2 into H'(t):
H'(1) = 32
H'(3) = -32
As you can see, the rate of change of the object's height goes from increasing to decreasing, meaning the critical point at t=2 is a maximum.
To find the height, plug t=2 into H(t):
H(2) = -16(2)^2 +64(2) + 30 = 94
The answer is 94 ft at 2 sec.
Answer:
B
Step-by-step explanation: