Answer:
The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.
This means that 
80% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).
Answer: Yes, No
Step-by-step explanation:
1st table is linear because the slope is always constant.
Second is not linear, but rather exponential.
Answer:
m/5 is one term and it is separated by 4*6 by add sign there are two terms
Step-by-step explanation:
hope this helps.
No problem just send those goldfish pics and some of those trash pics answer is 10