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2 years ago

Ken, a meteorologist, is predicting next year’s temperatures in New York City.

Mathematics

2 answers:

Shalnov [3]2 years ago

4 0

16 by Celsius
20C- 4C = 16C

omeli [17]2 years ago

4 0

20°C - 4°C = 16° C
it’s the same as normal math you just add the signs and symbols on it. hope this helped!

You might be interested in

<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cint%20t%5E2%2B1%20%5C%20dt" id="TexFormula1" title="\frac{d}{dx} \

Kisachek [45]

Answer:

$\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} \ = \ 2x^5-8x^2+2x-2$

Step-by-step explanation:

$\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} = \ ?$

We can use Part I of the Fundamental Theorem of Calculus:

$\displaystyle\frac{d}{dx} \int\limits^x_a \text{f(t) dt = f(x)}$

Since we have two functions as the limits of integration, we can use one of the properties of integrals; the additivity rule.

The Additivity Rule for Integrals states that:

$\displaystyle\int\limits^b_a \text{f(t) dt} + \int\limits^c_b \text{f(t) dt} = \int\limits^c_a \text{f(t) dt}$

We can use this backward and break the integral into two parts. We can use any number for "b", but I will use 0 since it tends to make calculations simpler.

$\displaystyle \frac{d}{dx} \int\limits^0_{2x} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}$

We want the variable to be the top limit of integration, so we can use the Order of Integration Rule to rewrite this.

The Order of Integration Rule states that:

$\displaystyle\int\limits^b_a \text{f(t) dt}\ = -\int\limits^a_b \text{f(t) dt}$

We can use this rule to our advantage by flipping the limits of integration on the first integral and adding a negative sign.

$\displaystyle \frac{d}{dx} -\int\limits^{2x}_{0} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}$

Now we can take the derivative of the integrals by using the Fundamental Theorem of Calculus.

When taking the derivative of an integral, we can follow this notation:

$\displaystyle \frac{d}{dx} \int\limits^u_a \text{f(t) dt} = \text{f(u)} \cdot \frac{d}{dx} [u]$
where u represents any function other than a variable

For the first term, replace $\text{t}$ with $2x$ , and apply the chain rule to the function. Do the same for the second term; replace

$\displaystyle-[(2x)^2+1] \cdot (2) \ + \ [(x^2)^2 + 1] \cdot (2x)$

Simplify the expression by distributing $2$ and $2x$ inside their respective parentheses.

$[-(8x^2 +2)] + (2x^5 + 2x)$
$-8x^2 -2 + 2x^5 + 2x$

Rearrange the terms to be in order from the highest degree to the lowest degree.

$\displaystyle2x^5-8x^2+2x-2$

This is the derivative of the given integral, and thus the solution to the problem.

6 0

3 years ago

A furniture rental company charges a fixed amount plus a fee based on the number of days for which the furniture is rented. The

baherus [9]

The fixed amount is the amount charged for 0 days' rental. The ordered pair (0, 80) tells you it is $80.

7 0

4 years ago

Read 2 more answers

Is the equation true false or open<br> (12+8)/-10=-12/6

kolbaska11 [484]

The equation is true 20/-10=-12/6 or -2=-2

8 0

3 years ago

The following is a composite figure. Find the TOTAL AREA of

vampirchik [111]

128 inches
for area , you multiply length times height so it’d be 16 x 8 :)

3 0

3 years ago

How to get the right answer

slavikrds [6]

You could break down the shape and then get to the area but there is a better way.

The picture looks like a rectangle with a chunk pulled off it.

Let just imagine that it was a perfect rectangle.

Its dimensions would be 57 by 36 (20+16).

Perfect Rectangle Area = 57x36 = 2052 $cm^{2}$

Now, let us find the area of the indent and subtract that from the previous area.

Indent Area = 16 x (57-15-15) = 16x27 = 432 $cm^{2}$

Real Area = 2052 $cm^{2}$ - 432 $cm^{2}$ = 1620 $cm^{2}$

answer = 1620 $cm^{2}$

4 0

3 years ago