3: 8h+24 4: 6h+21 5: 15x+45y 6: 44h+12g
7: 7jk first box 12jm second box. 8: 9ab+13a
Basically you just want to multiply the number outside the parentheses to each number inside them.
<h2><em>we can write (3x^2-5y^2) as (3x-5y)^2</em></h2><h2><em>(
3
x
−
5
y
)
2 as (
3
x−
5
y
)
(
3
x−
5
y
)</em></h2><h2><em>3
x
(
3
x
−
5
y
)
−
5
y
(
3x
−5
y
)</em></h2><h2><em>3
x
(
3
x
−
5
y
)
−
5
y
(3
x
−
5
y
)</em></h2><h2><em>3
x
(
3
x
)
+
3
x
(
−
5y
)
−
5
y
(
3
x
)
−
5
y(
-5
y
)</em></h2><h2><em>9
x
2
−
15
x
y
−
15y
x
+
25
y
2
</em></h2><h2><em> Subtract 15
y
x from −
15
x
y
.</em></h2><h2><em>9
x
2
−
30
xy
+
25
y
2</em></h2><h2><em> HOPE IT HELPS(◕‿◕✿) </em></h2><h2><em> SMILE!! </em></h2>
1. B, dependent variable
2. C, the dependent variable is represented in the 2nd column of a table.
8.
A. Domain: { 0, -3, 4, 5 }
B. Range: { 0, 1, 6, 7, 8 }
C. No, this is not a function because the x-value of 4 (domain) has two corresponding y-values of 6 and 8 (range)
Answer:
It 6
Step-by-step explanation:
