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svp [43]
3 years ago
13

Why does the light in space travel like a wave

Physics
2 answers:
Thepotemich [5.8K]3 years ago
7 0

Answer:

basic answer, radiation.

maksim [4K]3 years ago
3 0
Radiation, but hola have a great day pretty<3
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Newton's first law states that objects do not change their motion unless acted upon by a net force. What does the word 'net' mea
ollegr [7]
Answer it is b is the best option to pick A, does that make sense
7 0
4 years ago
Points A and B lie above an infinite plane of negative charge that produces a uniform electric field of strength E=10 N/C. What
olasank [31]

There is no illustration of the problem provided but I'll attempt to provide an answer.

The relationship between the electric potential difference between two points and the average strength of the electric field between those two points is given by:

║E║ = ΔV/d

║E║ is the magnitude of the average electric field, ΔV is the potential difference between A and B, and d is the distance between A and B.

We are given the following values:

║E║= 10N/C

d = 3m

Plug these values in and solve for ΔV

10 = ΔV/3

ΔV = 30V

4 0
4 years ago
What is the averge speed of a car that travels 800 mi in 5.5 hrs
german

Answer:

around 50 miles per hour is the answer i believe :)

Explanation:

6 0
3 years ago
Slove the following equation for v <br> A=v/t
LenKa [72]

If you meant solve, the answer would be v= A times t

You see, to get rid of an variable on one side, you must do the opposite of what is being done to it, in this case, multiply because division. After this, we must do what we did to one side to the other side. This creates the equation above!

7 0
3 years ago
A flywheel with a very low friction bearing takes 1.6 h to stopafter the motor power
Nina [5.8K]

Answer:

(I). The initial rotation rate is 4.29 rad/s.

(II). The revolutions is 3932.

Explanation:

Given that,

Time = 1.6 h

Angular velocity = 41 rpm

(I). We need to calculate the initial rotation rate in rad/s

\omega=41\ rev/m

\omega=\dfrac{41\times 2\pi}{60}\ rad/s

\omega=4.29\ rad/s

(II). We need to calculate the revolutions

Using formula of revolutions

\theta=\omega t

\theta=4.29\times1.6\times3600

\theta=24710\ rad

\theta=\dfrac{24710}{2\pi}

\theta=3932\ revolution

Hence, (I). The initial rotation rate is 4.293 rad/s.

(II). The revolutions is 3932.

7 0
4 years ago
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