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Troyanec [42]
3 years ago
6

Where would you look for some “original” planetesimals left over from the formation of our solar system?

Physics
1 answer:
alexandr402 [8]3 years ago
6 0

Answer:

Asteroid Belt and Kuiper belt

Explanation:

When solar system was forming a the leftover material was concentrated in Asteroid belt (between Mars and Jupiter) and Kuiper belt (which starts just after the orbit of Neptune). These two belts contain various small bodies called as planetesimals or asteroids which can give a lot of information about the early solar system.

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Que fracción de luz que llega directa a una lamina de vidrio se refleja en la primera superficie?
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unos 40 o30 pienso

Explanation:

7 0
3 years ago
Liquefaction _____.
gogolik [260]

Answer:

D).happens when soil is weakened by water and seismic waves              

Explanation:

Liquefaction is a phenomenon in which the strength of the soil weakens due to the earthquake or any other load. The solid behaves like a liquid. Liquefaction of soil below structures cause lot of damage during Earthquakes.The soil looses stiffness due to seismic waves and water.

Thus, the correct option is D.

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3 years ago
An ion has 8 protons and 10 electrons. What is the total charge? *
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3 years ago
What is the pair of vectors if summed , would create of equilibrium (a resultant of 0i + 0j) ?
bogdanovich [222]
<u>ANY</u> pair of vectors can produce that resultant, as long as ...

If one of the vectors is V₁ = A i + B j . . . . . . where 'A' and 'B' are <u>any</u> two numbers,

then the other one is V₂ = -A i - B j


6 0
4 years ago
Read 2 more answers
Two charged particles are accelerated through a uniform electric field and zero magnetic field, then enter a region with zero el
Mrac [35]

Answer:

Explanation:

In magnetic field , charged particle will have circular path . Let the radius of their circular path be r₁ and r₂ . Let their velocity at the time of entering magnetic field be v₁ and v₂ .

The velocity with which they will come out of electric field can be measured from following equation

Eq = 1/2 m v²  , E is electric field , q is charge on the particle , m is mass and v is velocity .

v² = 2Eq / m

radius of circular path can be measured by the following expression

m v² / r = Bqv

2Eq / r = Bqv

r = 2Eq / Bqv

= 2E / Bv

r² = 4E² / B²v²

= 4E²m / B²x 2Eq

since E , B and q are constant

r² = K . m

r₂² / r₁² = m₂ / m₁

1.5²

m₂ / m₁ = 1.5²

= 2.25

6 0
3 years ago
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