Radiant energy is the energy of electromagnetic and gravitational radiation
Answer:
A general solution is 
and a particualr case is mgh, it is just to distance around the radius Earth.
Explanation:
We can use a general equation of the potential energy to understand the particular and general case:
The potential energy is defined as 
, we know that the gravitational force is 
, so we could find the potential energy taking the integral of F.
(1)
We can find the particular case, just finding the gravitational potential energy difference:
. Here Uf is the potential evaluated in r+Δh and Ui is the potential evaluated in r.
Using (1) we can calculate ΔU.
Simplifying and combining terms we have a simplified expression.
(2)
Let's call 
. It is the acceleration due to gravity on the Earth's surface, if r is the radius of Earth and M is the mass of the Earth and we can write (2) as ΔU=mgh, but if we have distance grader than r we should use (2), otherwise, we could get incorrect values of potential energy.
I hope i hleps you!
Distance of first instance = speed * Time
= 60 * 3 = 180 miles
Distance of second instance = speed * Time
= 24 * 5 = 120 miles
So, Total Distance = 180 + 120 = 300 miles
In short, Your Answer would be 300 miles
Hope this helps!
By definition, when the speed of the light changes when it passes from a material to another, this is called "Refraction of light". This happens when there is a difference in the index of refraction between both mediums o materials. Therefore, that speed depends of <span>the medium through it passes.
</span>
T<span>he index of refraction</span> is expressed as below:
n=c/v
"n" is <span>the index of refraction.
</span> "c" is <span>is the speed of light.
</span> "<span>v" is the phase velocity of light in the medium.
</span>
A prism, a magnifying glass, a microscope, and eyeglasses refract light. Therefore, the correct option is: B) They refract light.
Answer:
the diameter of the smaller vessels is 9.90 mm
Explanation:
The computation of the diameter of the smaller vessels is given below;
Given that
The larger vessel of the diameter is 14mm
So,
d1 = 7 mm
let us assume the diameter of the smaller artery is d2
Now we used the equation of continuity i.e.
v × pi × d1^2 = 2 × v × pi × d2^2
14^2 = 2 × d2^2
d2 = 9.90 mm
Hence, the diameter of the smaller vessels is 9.90 mm
