What would make oppositely charged objects attract each other more?

You overhear two students discussing the topic of Doppler shift.

9966 [12]

Answer:

agree with student 2, disagree with student 1

Explanation:

If you want to know if the wavelength of light was shifted you have to know the original wavelengths

Since we know the absorption spectrum for elements like hydrogen, we can look for these absorption lines in the star's spectra and figure out what direction these lines are shifted and tell if the star is moving away or towards us

The color of the star refers to the temperature of the star's surface which is not related to the doppler shift of the star

5 0

4 years ago

(a) Suppose a meter stick made of steel and one made of invar are the same length at 0°C. What is their difference in length at

dem82 [27]

Explanation:

Given that,

Initial temperature $T_{i}=0^{\circ}C$

Final temperature $T_{f}=48.0^{\circ}C$

Length = 34.0 m

We know that,

Coefficient of linear expansion of Invar is

$\alpha=0.9\times10^{-6}/^{\circ}C$

Coefficient of linear expansion of steel is

$\alpha=12\times10^{-6}/^{\circ}C$

We need to calculate the temperature difference is

$\Delta T=T_{f}-T_{i}$

$\Delta T=48.0-0$

$\Delta T=48.0^{\circ}C$

We need to calculate the change in length of Invar

Using formula of change in length

$\Delta l=l\times\alpha\times\Delta t$

Put the value into the formula

$\Delta l=34\times0.9\times10^{-6}\times48.0$

$\Delta l=0.0014688=1.47\times10^{-3}\ m$

$\Delta l= 1.47\ mm$

We need to calculate the change in length of steel

$\Delta l'=34\times12\times10^{-6}\times48.0$

$\Delta l'=0.019584=19.59\times10^{-3}\ m$

$\Delta l'=19.59\ mm$

Difference in length of two 34.0 m

Long surveyor's tapes is

$\Delta L=\Delta l'-\Delta l$

Put the value into the formula

$\Delta L=19.59-1.47=18.12\ mm$

The difference in length is 18.12 mm.

Hence, This is the required solution.

6 0

3 years ago

A constant force of 120 N pushes a 55 kg wagon across an 8 m level surface. If the wagon was initially at rest, what is the fina

Illusion [34]

Answer:

The kinetic energy of the wagon is 967.0 J

Explanation:

Given that,

Force = 120 N

Mass = 55 kg

Height = 8 m

We need to calculate the kinetic energy of the wagon

Using newtons law

$F = ma$

$\dfrac{120}{55}=a$

$a =2.2\ m/s^2$

Using equation of motion

$v^2 =u^2+2as$

Where,

v = final velocity

u = initial velocity

s = height

Put the value in the equation

$v^2=0+2\times2.2\times8$

$v=5.93\ m/s$

Now, The kinetic energy is

$K.E=\dfrac{1}{2}mv^2$

$K.E=\dfrac{1}{2}\times55\times(5.93)^2$

$K.E=967.0\ J$

Hence, The kinetic energy of the wagon is 967.0 J

3 0

3 years ago

Determine the value of V3 in volts where Vs = 15V, V1 = 5V, and V2 = 3V. Put the value of V3 in the box below without the units.

marshall27 [118]

Answer:

The value of V₃ is 7 V

enter value =7

Explanation:

Given that,

Source voltage $V_{s}=15 V$

First voltage $V_{1}=5V$

Second voltage $V_{2}=3V$

According to figure,

We need to calculate the value of third voltage

Using Kirchhoff voltage law

$V_{s}+V_{1}+V_{2}+V_{3}=0$

$-15+5+3+V_{3}=0$

$v_{3}=7\ V$

Hence, The value of V₃ is 7.

4 0

3 years ago

What is the Force of an object that has a mass of 35 Kg and an acceleration of 25 m/s/s?

Diano4ka-milaya [45]

Answer:

<h2>The answer is option D</h2>

Explanation:

The force acting on an object can be found by using the formula

<h3>force = mass × acceleration</h3>

From the question

mass = 35 kg

acceleration = 25 m/s²

We have

force = 35 × 25

We have the final answer as

Hope this helps you

3 0

3 years ago