F(1)=2, f(n)= f(n-1)+7 Plsss help

H/7 =27 can some one answer this pls

Lesechka [4]

Answer:

h=189

Step-by-step explanation:

solve for H by simplifying both sides of the equation, then isolating the variable.

hope this helped

3 0

3 years ago

The parabola y = x² - 4 opens: A.) up B.) down C.) right D.) left

fomenos

Answer:

Up

Step-by-step explanation:

Here the easy rules to remember the orientation of the parabolas are

a) If x is squared it opens up or down. And its coefficient of { $x^{2}[tex] is negative it opens down.b) If y is squared it opens side ways right or left. It its coefficient of [tex]y^{2}$

Hence in our equation of parabola

$y = x^ 2-4$

x is squared and its coefficient is positive , hence it opens up towards positive y axis.

3 0

2 years ago

Jake forgot to replace the cap on a bottle of cologne. The cologne began to evaporate at the rate of 18% per day. If the origina

Cerrena [4.2K]

Answer:

x is 738

Step-by-step explanation:

6 0

2 years ago

6 times the sum of a number and 5 is 16

Ulleksa [173]

The equation would be 6 times x+5=16. This would be kinda Impossible. But a really close answer is 1.833

8 0

3 years ago

part 2. Find the value of the trig function indicated, use for that Pythagorean theorem to find the third side if you need it.

andreev551 [17]

Answer: $\bold{5)\ \cos \theta=\dfrac{\sqrt{11}}{6}\qquad 6)\ \tan \theta =\dfrac{8}{17}\qquad 7)\ \cos \theta = \dfrac{4}{3}\qquad 8)\ \cos \theta = \dfrac{\sqrt{10}}{10}}$

Step-by-Step Explanation:

Pythagorean Theorem is: a² + b² = c² , where "c" is the hypotenuse

$5)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{3\sqrt{11}}{18}\quad \rightarrow \large\boxed{\dfrac{\sqrt{11}}{6}}$

Note: (15)² + (3√11)² = hypotenuse² → hypotenuse = 18

$6)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{8}{17}\quad =\large\boxed{\dfrac{8}{17}}$

Note: 8² + 15² = hypotenuse² → hypotenuse = 17

$7)\ \tan \theta=\dfrac{\text{side opposite to}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{20}{15}\quad \rightarrow \large\boxed{\dfrac{4}{3}}$

Note: hypotenuse not needed for tan

$8)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{2}{2\sqrt{10}}\quad =\large\boxed{\dfrac{\sqrt{10}}{10}}$

Note: 2² + 6² = hypotenuse² → hypotenuse = 2√10

8 0

2 years ago