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1 year ago

Need help. Solve for x, geometry

Mathematics

1 answer:

motikmotik1 year ago

8 0

Answer:

9) x = 4 D)

10) x = 7 B)

Step-by-step explanation:

Vertical angles are congruent.

23x - 2 = 90

23x = 92

x = 4

10)

Vertical angles are congruent.

18x - 6 = 1 + 17x

x = 7

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2 years ago

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2 years ago

What is the solution to the equation? 4√x-4 =3 <br><br> A. -8 B. 16 C. 85 D. no solution

kodGreya [7K]

${\qquad\qquad\huge\underline{{\sf Answer}}}$

Here we go ~

$\qquad \sf \dashrightarrow \: \sqrt[4]{x - 4} = 3$

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1 year ago

Read 2 more answers

Find the line integral of f⃗ (x,y,z)=x3i⃗ +y2j⃗ +zk⃗ along the line segment c from the origin to the point (2,3,9).

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The path $\mathcal C$ can be parameterized by the vector-valued function,

$\mathbf r(t)=t(2\,\mathbf i+3\,\mathbf j+9\,\mathbf k)$

where $0\le t\le1$ . Then

$\mathrm d\mathbf r=(2\,\mathbf i+3\,\mathbf j+9\,\mathbf k)\,\mathrm dt$

The line integral reduces to

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=0}^{t=1}(x(t)^3\,\mathbf i+y(t)^2\,\mathbf j+z(t)\,\mathbf k)\cdot(2\,\mathbf i+3\,\mathbf j+9\,\mathbf k)\,\mathrm dt$

$=\displaystyle\int_{t=0}^{t=1}((2t)^3\,\mathbf i+(3t)^2\,\mathbf j+9t\,\mathbf k)\cdot(2\,\mathbf i+3\,\mathbf j+9\,\mathbf k)\,\mathrm dt$

$=\displaystyle\int_{t=0}^{t=1}(16t^3+27t^2+81t)\,\mathrm dt=\frac{107}2$

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2 years ago