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3 years ago

Kite GHIJ has sides GH, HI, IJ and JG. What are the diagonals of this figure? Select all that apply.

Mathematics

1 answer:

juin [17]3 years ago

6 0

Answer:

GI or HJ

Step-by-step explanation:

Diagonals connect non-adjacent vertices.

That is, the diagonal with G as an endpoint will not connect to vertices H or J, but will connect to vertex I. Likewise the diagonal with H as one end will have J as the other end. A quadrilateral has only two (2) diagonals. Of course, each can be named two ways:

GI or IG

HJ or JH

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10 divided by 2-(16 divided by 4) +14

ankoles [38]

Answer:

Step-by-step explanation:

okay so you gotta use pemdas (p = parentheses, e = exponents, m = multiplication, d = division, a = addition, s = subtraction), but for the multiplication/division and addition/subtraction parts, if division or subtraction happens first then you must do it first rather than doing multiplication or addition first

10 / 2 -(16/4) + 14

10 / 2 -(4) + 14

5 - 4 + 14

1 + 14

7 0

3 years ago

Read 2 more answers

A quality analyst of a tennis racquet manufacturing plant investigates if the length of a junior's tennis racquet conforms to th

Burka [1]

Answer:

Confidence interval : $21.506$ to $24.493$

Step-by-step explanation:

A quality analyst selects twenty racquets and obtains the following lengths:

21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

So, sample size = n =20

Now we are supposed to find Construct a 99.9% confidence interval for the mean length of all the junior's tennis racquets manufactured at this plant.

Since n < 30

So we will use t-distribution

Confidence level = 99.9%

Significance level = α = 0.001

Now calculate the sample mean

X=21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

Sample mean = $\bar{x}=\frac{\sum x}{n}$

Sample mean = $\bar{x}=\frac{21+25+23+22+24+21+25+21+23+ 26+ 21+24+22+ 24+23+21+ 21+ 26+23+ 24}{20}$

Sample mean = $\bar{x}=23$

Sample standard deviation = $\sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}$

Sample standard deviation = $\sqrt{\frac{(21-23)^2+(25-23)^2+(23-23)^2+(22-23)^2+(24-23)^2+(21-23)^2+(25-23)^2+(21-23)^2+(23-23)^2+(26-23)^2+(21-23)^2+(24-23)^2+(22-23)^2+(24-23)^2+(23-23)^2+(21-23)^2+(21-23)^2+(26-23)^2+(23-23)^2+(24-23)^2}{20-1}}$

Sample standard deviation= s = $1.72$

Degree of freedom = n-1 = 20-1 -19

Critical value of t using the t-distribution table $t_{\frac{\alpha}{2}$ = 3.883

Formula of confidence interval : $\bar{x} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}}$

Substitute the values in the formula

Confidence interval : $23 \pm 1.73 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $23 -3.883 \times \frac{1.72}{\sqrt{20}}$ to $23 + 3.883 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $21.506$ to $24.493$

Hence Confidence interval : $21.506$ to $24.493$

3 0

4 years ago

Read 2 more answers

Solve for x.<br> 25x=30<br> Simplify your answer as much as possible.

irinina [24]

Answer:

x = 750

Explanation:

25x = 30

1. Multiply 25 by 30

25 * 30 = 750

2. Divide 750 by 25

750/25 = 30

3. Divide 750 by 30

750/30 = 25

Therefore, x = 750

3 0

3 years ago

Read 2 more answers

L (3 x 6) (5 x 2 4-7

Verdich [7]

The answer would be 4

8 0

3 years ago

Please help me with these two problems I need help

sweet [91]

Answer:

24 area

18.80983669 perimeter

Step-by-step explanation:

1 (6*3/2)*2(1*3/2)+(4*3)

2 trust me

7 0

3 years ago