the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
Range is the difference between the largest and the smallest variable. If the range is 18 and the smallest number is 9. Add 9 to 18.
9+18= 27. 27 is the largest number.
Answer:
(x, y) ≈ (2.848, -19.241)
Step-by-step explanation:
I find it much easier to work with the problem statement when math expressions are written using numbers and symbols. We assume you have ...
-4x +15y = -300
20x +4y = -20
Dividing the second equation by 4 and subtracting the x-term gives ...
y = -5-5x
Substituting that into the first equation, we get ...
-4x +15(-5-5x) = -300
-79x -75 = -300
x = -225/-79 = 2 67/79 ≈ 2.8481
Substituting this into the equation for y gives ...
y = -5(x +1) = -5(3 67/79) = -19 19/79 ≈ -19.2405
The approximate solution is ...
(x, y) = (2.8481, -19.2405)
17+4=21
21 divided by 3= 7
17 dollars for tickets
21-4=17
so your answer is 21 he has to sweep the floor 21 times to get tickets
