Answer:
1. (2x^2+x-1)
Step-by-step explanation:
expanding (2x^2-1)^2. multiplying (x-2) (1-2x)
= 4x^2-4x+1. = x-2x^2-2+4x
= -2x^2+5x-2
(4x^2-4x+1-2x^2+5x-2)
=2x^2+x-1
< the bigger number is facing the back of the arrow it points to the smaller number Example: 1<2
Let us find the co ordinates of each vertex of the triangle .
Vertex A ( in firs second quadrant) = ( -5 ,3)
vertex B in third quadrant = ( -5, -5)
vertex C in fourth quadrant = ( 4, -2)
let us use distance formula AB^2 = ( -5 - 3)^2 + (-5 - -5 )^2 = 64 + 0
AB= 8
BC^2 = ( -2 - -5 )^2 + ( 4 - - 5)^2 = 9 + 81 = 90
BC = 9.48
AC^2 = ( -2 -3)^2 +( 4- -5)^2 = 25 + 81 = 106
AC= 10.29
Perimeter = sum of length of AB+ BC+ Ac = 8 + 10.29 + 9.48= 22.77
Answer:
add the negative to the 0 that is left alone at the end then carry the x2 over to the side bringing it down with the x and cancel them taking away the 2. the answer is -1
Step-by-step explanation:
