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MakcuM [25]
3 years ago
12

8 to 14 as a ratio as a fraction in simplest form.

Mathematics
2 answers:
aksik [14]3 years ago
8 0
4:7 4/7
The greatest common factor is 2
8/2=4
14/2=7
padilas [110]3 years ago
3 0

Answer:

4/7 or 4:7

Step-by-step explanation:

8/14 divided by 2= 4/7

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2 2/3 multiplied by 5 4/5
grin007 [14]
2 \frac{2}{3} = \frac{8}{3} 

5  \frac{4}{5} =  \frac{29}{5}
\frac{8}{3} * \frac{29}{5} =X
Solve for X. What do you think the answer is based on that?
8 0
3 years ago
Use the given conditions to write an equation for each line in general form.
Aneli [31]

Answer:

It's the last choice:

2x + y - 1 = 0.

Step-by-step explanation:

x - 2y - 3 = 0

Convert to slope-intercept form in order to find the slope:

-2y = -x + 3

y = 1/2x - 3/2

So the slope  is 1/2.  The slope of a line perpendicular to this is -1 / 1/2 = -2.

Using the point-slope form to find  the required equation:

y - y1 = m(x - x1)

x = 4 and y = -7 so we have:

y + 7 = -2(x - 4)

y + 7 = -2x + 8

2x + y - 1 = 0  is the answer.

6 0
3 years ago
Keisha is preparing cookie boxes for her 4 teachers.She has 36 surgar cookies and 24 chocolate chip cookies.How many cookies Wil
Flauer [41]

\text{We know that Keisha has 36 sugar cookies}\\\\\text{We also know that she has 24 chocolate chip cookies}\\\\\text{We wants to evenly distribute these cookies to her 4 teachers}\\\\\text{First, find the total amount of cookies by adding 36 and 24}\\\\36+24=60\\\\\text{Now divide by 4 to see how many cookies you have to give to each teacher}\\\\60\div4=15\\\\\boxed{\text{Your answer would be 15 cookies}}

4 0
3 years ago
Use polar coordinates to find the volume of the given solid. Inside both the cylinder x2 y2 = 1 and the ellipsoid 4x2 4y2 z2 = 6
Anton [14]

The Volume of the given solid using polar coordinate is:\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

V= \frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

<h3>What is Volume of Solid in polar coordinates?</h3>

To find the volume in polar coordinates bounded above by a surface z=f(r,θ) over a region on the xy-plane, use a double integral in polar coordinates.

Consider the cylinder,x^{2}+y^{2} =1 and the ellipsoid, 4x^{2}+ 4y^{2} + z^{2} =64

In polar coordinates, we know that

x^{2}+y^{2} =r^{2}

So, the ellipsoid gives

4{(x^{2}+ y^{2)} + z^{2} =64

4(r^{2}) + z^{2} = 64

z^{2} = 64- 4(r^{2})

z=± \sqrt{64-4r^{2} }

So, the volume of the solid is given by:

V= \int\limits^{2\pi}_ 0 \int\limits^1_0{} \, [\sqrt{64-4r^{2} }- (-\sqrt{64-4r^{2} })] r dr d\theta

= 2\int\limits^{2\pi}_ 0 \int\limits^1_0 \, r\sqrt{64-4r^{2} } r dr d\theta

To solve the integral take, 64-4r^{2} = t

dt= -8rdr

rdr = \frac{-1}{8} dt

So, the integral  \int\ r\sqrt{64-4r^{2} } rdr become

=\int\ \sqrt{t } \frac{-1}{8} dt

= \frac{-1}{12} t^{3/2}

=\frac{-1}{12} (64-4r^{2}) ^{3/2}

so on applying the limit, the volume becomes

V= 2\int\limits^{2\pi}_ {0} \int\limits^1_0{} \, \frac{-1}{12} (64-4r^{2}) ^{3/2} d\theta

=\frac{-1}{6} \int\limits^{2\pi}_ {0} [(64-4(1)^{2}) ^{3/2} \; -(64-4(2)^{0}) ^{3/2} ] d\theta

V = \frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

Since, further the integral isn't having any term of \theta.

we will end here.

The Volume of the given solid using polar coordinate is:\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

Learn more about Volume in polar coordinate here:

brainly.com/question/25172004

#SPJ4

3 0
1 year ago
Find the area of each sector.
nevsk [136]

Answer:

225

Step-by-step explanation:

360 - 135 = 225

7 0
3 years ago
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