Use the diagram to find the angle measures of triangle. Recall that the sum of the angle measures of a triangle 180

11A. Lakewood Towing Company charges $50 plus $4 per mile to tow

aleksandr82 [10.1K]

Answer:

15 miles

Step-by-step explanation:

50 + 4x = 80 + 2x

-50 -2x = -50 -2x

2x = 30

x = 15

7 0

3 years ago

PLEASEE HELP ASAPPPP!<br> x9/x4 <br> PLEASSEEEEEEEE

Semmy [17]

Answer:

x^5

Step-by-step explanation

If this is dividing exponents, you just subtract the denominator from the numerator.

5 0

3 years ago

I am a 4 digit number larger than 2,500. No two of my digits are the same. The product of the thousands digit and the hundreds d

gulaghasi [49]

Answer:

After 5 minutes of hitting my head on a wall I found your answer... 3256

Step-by-step explanation:

4 0

3 years ago

What is the value of x?<br> Please help fast will give brainliest help fast

serious [3.7K]

Answer:

17

Step-by-step explanation:

because of the kind of angle it is, the two equations are equal. So, put the equations equal to each other and solve:

x+35=3x+1

combine like terms (by subtracting)

2x=34

isolate x by dividing by 2

x=17

17

8 0

3 years ago

Read 2 more answers

Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ

atroni [7]

Answer: $y=Ce^(^3^t^{^9}^)$

Step-by-step explanation:

Beginning with the first differential equation:

$\frac{dy}{dt} =27t^8y$

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

$\frac{1}{y} \frac{dy}{dt} =27t^8$

Multiply both sides by 'dt' to get:

$\frac{1}{y}dy =27t^8dt$

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

$\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt$

$ln(y)=27(\frac{1}{9} t^9)+C$

$ln(y)=3t^9+C$

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

$e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)$

$y=e^(^3^t^{^9} ^+^C^)$

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

$y=e^(^3^t^{^9}^)e^C$

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

$y=Ce^(^3^t^{^9}^)$

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

$\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8$

Now check if the derivative equals the right side of the original differential equation:

$(Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)$

$Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)$

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

7 0

2 years ago