The cell membrane allows this to be true
The cubs are a significant barrier to reproduction when a new male coalition first takes control of a pride. Mothers of surviving cubs won't mate again until their young are at least 18 months old, but if their cubs are lost, they will mate right away.
- Following that, males leave on their own or are driven out by other men who take control of their pride. It is common for a new male to kill all the cubs when he joins the pride in order to pass his genes on to all future cubs. The major function of males in the pride is defending the pride's territory.
- Female lionesses will devour the cubs of other pride, but not the cubs of their own pride. The "egalitarianism" of female lions stands in stark contrast to the autocratic behavior of wolves, wild dogs, and several other species, where dominant females prevent subordinates from reproducing.
- When a female lion gives birth, she leaves the pride and doesn't come back until the cubs are several weeks old. After that, the adult females band together to take care of and protect the young.
Learn more about pride here:
brainly.com/question/17454996
#SPJ4
Answer:
Insertion
Explanation:
An insertion is the addition of one or more nucleotide base pairs into a DNA sequence.
In this case, T was added to the strand
Answer:
1/8
Explanation:
Given that the trihybrid parents have AaBbCc genotype for fruit color. The trait is a quantitative trait i.e. each dominant allele will have an additive effect on it. In this case, AaBbCc and AABBCC will not produce same fruit color because AaBbCc has only three loci contributing to the color while in AABBCC all the six loci are contributing to the color. For an offspring to be exactly similar to the AaBbCc parents it should have the same genotype of AaBbCc.
The probability of Aa to come from a cross between Aa and Aa is 2/4 or 1/2
The probability of Bb to come from a cross between Bb and Bb is 2/4 or 1/2
The probability of Cc to come from a cross between Cc and Cc is 2/4 or 1/2
So the collective probability of AaBbCc offspring from a cross between AaBbCc and AaBbCc parents would be=
1/2 * 1/2 * 1/2 = 1/8
Hence, assuming no effects of the environment, 1/8 of the offspring will have the same fruit color phenotype as the trihybrid parent.
D I think sorry if it’s wrong ♀️