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4 years ago

12

F 15 g of C₂H₆ reacts with 60.0 g of O₂, how many moles of water (H₂O) will be produced? (Hint: use what you know about limiting

reactant) *
10 points

1 answer:

Mars2501 [29]4 years ago

4 0

Answer:

1.5 mol H2O

Explanation:

2C2H6 + 7O2 -> 4CO2 + 6H2O

The limiting reactant is C2H6

30 g C2H6 ->1 mol C2H6

15 g C2H6 -> x x= 0.5 mol C2H6

2 mol C2H6 -> 6 mol H2O

0.5 mol c2H6 -> x x = 1.5 mol H2O

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It increases. B.

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Carbon dioxide gas occupies a volume of 20.0 L at 308K and 2.30 atm. What volume would it occupy at 416 K and 5.40 atm?

Brrunno [24]

Answer : The final volume of gas is, 11.5 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

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where,

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3 years ago

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4 years ago

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The reaction between NaOH and HCl is as follows
NaOH + HCl ---> NaCl + H₂O
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Since there's excess OH⁻ ions, we can calculate pOH value first
pOH = - log [OH⁻]
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3 years ago

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