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Serggg [28]
4 years ago
12

F 15 g of C₂H₆ reacts with 60.0 g of O₂, how many moles of water (H₂O) will be produced? (Hint: use what you know about limiting

reactant) *
10 points
Chemistry
1 answer:
Mars2501 [29]4 years ago
4 0

Answer:

1.5 mol H2O

Explanation:

2C2H6 + 7O2 -> 4CO2 + 6H2O

The limiting reactant is C2H6

30 g C2H6 ->1 mol C2H6

15 g C2H6   -> x                      x= 0.5 mol C2H6

2 mol C2H6 -> 6 mol H2O

0.5 mol c2H6 -> x                    x = 1.5 mol H2O

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Does a part or slice of a substance have a different density than the whole piece?<br><br> Pls help!
Nostrana [21]
Density is defined as mass per unit volume so even when you cut an object in half unit volume does not change so each part would have a different density even if it’s cut into the same pieces
3 0
3 years ago
How many grams of 48.0 wt% NaOH (FM 40.00) should be diluted to 1.00 L to make 0.11 M NaOH? (Enter your answer using two digits.
kifflom [539]

Answer:

The answer is 916.67 g

Explanation:

48.0 wt% NaOH means that there are 48 g of NaOH in 100 g of solution. With this information and the molecular weight of NaOH (40 g/mol), we can calculate the number of mol there are in 100 g of this solution:

\frac{48 g NaOH}{100 g solution} x \frac{1 mol NaOH}{40 g} = 0.012 mol NaOH/100 g solution

Finally, we need 0.11 mol in 1 liter of solution to obtain a 0.11 M NaOH solution.

0.012 mol NaOH ------------ 100 g solution

0.11 mol NaOH------------------------- X

X= 0.11 mol NaOH x 100 g/ 0.012 mol NaOH= 916.67 g

We have to weigh 916.67 g of 48.0%wt NaOH and dilute it in a final volume of 1 L of water to obtain a 0.11 M NaOH solution.

7 0
3 years ago
A 0.100-l sample of an unknown hno3 solution required 32.9 ml of 0.200 m ba(oh)2 for complete neutralization. what was the conce
ddd [48]
The reaction between HNO3 and Ba(OH)2 is given by the equation below;
2HNO3 + Ba(OH)2 = Ba(NO3)2 + 2H2O
Moles of Barium hydroxide used;
 = 0.200 × 0.039 l
 = 0.0078 Moles
The mole ratio of HNO3 and Ba(OH)2 is 2: 1
Therefore; moles of nitric acid used will be;
= 0.0078 ×2 = 0.0156 moles
But; 0.0156 moles are equal to a volume of 0.10
The concentration of Nitric acid will be; 
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 = 0.156 M
7 0
3 years ago
Read 2 more answers
I need help with these chem converions pleaseeee
Vlad [161]

Answer:

For the Extra Credit Question your answer is 6.307e+9

Explanation:

8 0
3 years ago
A certain chemical reaction releases of heat energy per mole of reactant consumed. Suppose some moles of the reactant are put in
m_a_m_a [10]

To relate the quantity of a substance to the amount of heat transferred and heat capacity, temperature, number of moles is given by

q=ncpΔT

where

n is number of moles

cp is molar heat capacity

ΔT=Tfinal−Tinitial is the temperature difference

8 0
3 years ago
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