The liquid inside the cell is called
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Given that the mass of coffee in the cup = 140 g
Final temperature =
Initial temperature =
Let us assume the specific heat of coffee is equal to that of water = 4.184
Temperature change = T(final) - T(initial) = (20 - 75 )
=- 55
-Heat given out by coffee = heat absorbed by the surroundings
Heat released into the surroundings =-()
=
= 32,217 J