Question

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Answer 1

DUDE JUST STUDY MEXT TIME

Answer 2

Answer:

2nd option

Step-by-step explanation:

given a quadratic in standard form

y = ax² + bx + c

• If a > 0 then minimum vertex

• If a < 0 then maximum vertex

Here a = - 1 < 0 then maximum

The maximum value is the value of the y- coordinate of the vertex

The x- coordinate of the vertex is

x = - $\frac{b}{2a}$

Here a = - 1 and b = 3 , then

x = - $\frac{3}{-2}$ = $\frac{3}{2}$

Substitute this value into the equation for corresponding y- value

y = - ($\frac{3}{2}$ )² + 3($\frac{3}{2}$ ) - 1 = - $\frac{9}{4}$ + $\frac{9}{2}$ - 1 = - $\frac{9}{4}$ + $\frac{18}{4}$ - $\frac{4}{4}$ = $\frac{5}{4}$

Then maximum value of $\frac{5}{4}$