Since both the expressions in x are equal to y then they are equal to each other, so
-2x + 3 = 13x - 4
-15x + 3 = -4
-15x = -7
x = 7/15
and y = -2(7/15) + 3 = 31/15 = 2 1/15
Answer:
200 trucks
Step-by-step explanation:
There's about 15 trucks in the 2nd row from the right. It looks to be about 1/2 the size of the rows to the left of it.
So based on that, I can assume, there are about 30 trucks in each of the 5 long rows, and both of the short rows would make up about another 30 trucks total. There are various trucks parked along the perimeter or between rows, so I estimated there would be about 20 of those based on 3 per row.
30 x 5 = 150 +30 = 180 + 20 = 200
Completing the square is done as follows:
1. Write the equation in a way that the constants are in the right side while the terms with x are on the left.
<span>9x2 +54x = 7
</span>
2. Make sure that the coefficient of the x^2 term is 1.
<span>9(x2 + 6x) = 7
</span>
3. Adding a term to both sides that will complete the square in the left side. This is done by dividing the coefficient of the x term by 2 and squaring it. Note: The same amount should be added to the right side to balance the equation.
<span>9(x2 + 6x + 9) = 7 + 81
9(x+3)^2 = 88
</span>
So first I would say, what if all of them were dimes, how far away would it be from $14?
So 92 coins * 10 cents = $9.20
So it's 4.80 dollars away from 14 dollars.
So if we were to switch one to a quarter, it would increase by 0.15 cents.
So we want to see how many increases we need to reach 4.80 dollars more.
4.80/0.15 = 32
So there are 32 quarters and 60 dimes.
Answer: The two sides are 15m and 10m.
Step-by-step explanation:
Area = l x w
150 = l x w
There are two solutions for l
l 1= P/4+1/4√P2﹣16A
=50/4+1/4·√50^2﹣16·150=15m
l2 = P/4﹣1/4√P2﹣16A
=50/4﹣1/4·√50^2﹣16·150=10m
