Set up a system of equations.
0.10d + 0.25q = 39.25
d + q = 250
Where 'd' represents the number of dimes, and 'q' represents the number of quarters.
d + q = 250
Subtract 'q' to both sides:
d = -q + 250
Plug in '-q + 250' for 'd' in the 1st equation:
0.10(-q + 250) + 0.25q = 39.25
Distribute 0.10:
-0.10q + 25 + 0.25q = 39.25
Combine like terms:
0.15q + 25 = 39.25
Subtract 25 to both sides:
0.15q = 14.25
Divide 0.15 to both sides:
q = 95
Now plug this into any of the two equations to find 'd':
d + q = 250
d + 95 = 250
Subtract 95 to both sides:
d = 155
So there are 95 quarters and 155 dimes.
-17+2(-3)^2
-17+2(9)
-17+18
1
Answer:
Given speed of trolley = 125 meters per minute
Now we know that
Distance= Speed x time
Thus for the first case since the time of travel is less than 450 seconds thus the distance traveled is less than
Distance < 2.083 x 450 =937.5 meters
hence depending on the given information we cannot come to any conclusion weather the distance travelled is less than 800 m or greater than 800 m.
For the second case
since the time of travel is greater than 400 seconds
Thus the distance traveled is
which is greater than 800 meters.
Step 1: Substitute the value of x into the equation
x= 3-3/2y
-3x+5y=10
Step 2: Solve the equation
-3(3-3/2y)+5y=10
Step 3: Substitute the value of y into the equation
Y=2
Step 4: Solve the equation
X=3-3/2×2 = X=0
Answer: (0,2)
Answer: 2x + 5y = - 10, Cy + 4 = (x-5)
Dy - 4 = (x+ 5)
Step-by-step explanation:
Equation of the line
5x - 2y = -6
Conditions for perpendicularity
m1 x m2 = -1
To get m1, rearrange the equation
2y = 5x + 6
y = 5x/2 + 3
n1 = 5/2 and m2 = -2/5
To get C
y = mx +c
-4 = -2 x 5/5 + C
-4 = -2 + C
C = -4 + 2
C = -2
To get the equation of the second line
y = -2x/5 - 2
Multiply through by 5
5y = -2x - 10
2x + 5y = 10.
