All categories

3 years ago

X + 4y = 16 -X + 3y = -2

Mathematics

1 answer:

jeyben [28]3 years ago

7 0

Answer:

(8, 2 )

Step-by-step explanation:

Given the 2 equations

x + 4y = 16 → (1)

- x + 3y = - 2 → (2)

Adding the 2 equations term by term will eliminate the x- term

0 + 7y = 14

7y = 14 ( divide both sides by 7 )

y = 2

Substitute y = 2 into either of the 2 equations and solve for x

Substituting into (1)

x + 4(2) = 16

x + 8 = 16 ( subtract 8 from both sides )

x = 8

solution is (8, 2 )

You might be interested in

The function F(x) log7 x is increasing.<br> A. True<br> B. False

Law Incorporation [45]

Answer:

The correct answer is A: True

Step-by-step explanation:

Since the log is greater than 1 it is going to increase

5 0

3 years ago

Read 2 more answers

Write the word sentence as an equation. Then solve.

Ainat [17]

Answer:

Solution: X=144

Equation: x/(-9)= -16

Step-by-step explanation:

the / is divide

the first part of the word problem states that a number x is being divided by -9, x/-9 then it states that this equation equals -16 therefore,x/-9=-16.

5 0

3 years ago

Read 2 more answers

Use the discriminant to determine the number of real solutions of the equation.<br> x^2 = -6x - 10

HACTEHA [7]

Answer:

No real solutions.

Step-by-step explanation:

x² + 6x + 10 = 0

a = 1

b = 6

c = 10

D = b² - 4ac = 6² - 4*1*10 = 36 - 40 = - 4

- 4 < 0,

so this equation has no real solutions.

8 0

3 years ago

Read 2 more answers

Find the area of the shaded region in this figure.

stealth61 [152]

Answer:

B) 190 cm^2

Step-by-step explanation:

Im pretty sure all you gotta do is

20x10 which is 200 then do 5x2

which is 10 and you minus 10 from 200

Please correct me if im wrong here

I dont really remember doing these

6 0

2 years ago

The area of a circular sun spot is growing at a rate of 1,200 km2/s.

Tpy6a [65]

A)

$\bf \textit{area of a circle}\\\\
A=\pi r^2
\\\\\\
\cfrac{dA}{dt}=\pi \cdot 2r\cfrac{dr}{dt}\implies \cfrac{dA}{dt}=2\pi r\cfrac{dr}{dt}\implies \cfrac{\frac{dA}{dt}}{2\pi r}=\cfrac{dr}{dt}\\\\
-----------------------------\\\\
\left. \cfrac{dr}{dt} \right|_{r=3000}\implies \cfrac{1200}{2\pi \cdot 3000}=\cfrac{dr}{dt}\\\\$

B)

$\bf A=\pi r^2\qquad A=490000\implies 490000=\pi r^2\implies \sqrt{\cfrac{490000}{\pi }}=r
\\\\\\
\left. \cfrac{dr}{dt} \right|_{r=\sqrt{\frac{490000}{\pi }}}\implies \cfrac{1200}{2\pi \cdot \sqrt{\frac{490000}{\pi }}}=\cfrac{dr}{dt}
$

8 0

3 years ago

X + 4y = 16 -X + 3y = -2 ​

X + 4y = 16 -X + 3y = -2