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ASHA 777 [7]
3 years ago
14

2. Gas A has twice as much mass as Gas B. Compared to one mole of gas A, one mole of

Chemistry
1 answer:
klio [65]3 years ago
4 0
I think the answer is d
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When 0.25 moles of NH3 are produced according to the reaction below, how many moles of H2 must have reacted?
marissa [1.9K]

Answer:

Explanation:

by stoichiometry

nNH3/2=nH2/3

0.25/2=nH2/3

nH2=0.25×3/2

nH2=0.375 mol

so its 0.38 mol

6 0
3 years ago
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How do metamorphic rocks form?
Orlov [11]
The correct answer is A
4 0
3 years ago
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Hydroxylapatite, Ca10(PO4)6(OH)2, has a solubility constant of Ksp = 2.34 x 10^-59. Solid hydroxylapatite is dissolved in water
nadezda [96]

Answer:

The concentration of [Ca²⁺] is 8.47 x 10⁻³ M

Explanation:

We consider the solubility of hydroxyapatite,

Ca₁₀(PO₄)₆(OH)₂ ⇔ 10Ca²⁺ + 6PO₄³⁻ + 2 OH⁻

Assumed that there is <em>a</em> mol of hydoxyapatite disolved in water, yielding <em>10a</em> mol Ca²⁺ of  and <em>6a</em> mol of PO₄³⁻

We also have Ksp equation,

Ksp = [Ca²⁺]¹⁰ x [PO₄³⁻]⁶ x [OH⁻]² = 2.34 x 10⁻⁵⁹

     ⇔  10a¹⁰ x 6a⁶ x (5.30 x 10⁻⁶)² = 2.24 x 10⁻⁵⁹

     ⇔  60a¹⁶                                    = 2.24 x 10⁻⁵⁹ / 5.30 x 10⁻¹²

     ⇔  a¹⁶                                         = 0.007 x 10⁻⁴⁷ = 7 x 10⁻⁵⁰

     ⇔  a                                           = \sqrt[16]{7 . 10^{-50} } =  8.47 x 10⁻⁴

Hence,

[Ca²⁺] = 10<em>a</em> = 8.47 x 10⁻³ M

3 0
4 years ago
Can some one help meeeeeee on
Salsk061 [2.6K]

Answer:

What are we helping you on?

Explanation:

..

4 0
3 years ago
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Ml of 0.00237 m nai (aq) is combined with 625. ml of 0.00785 m pb(no3)2 (aq). determine if a precipitate will form given that th
Talja [164]
The volume of I- is missing in your question by assuming it = 1L
moles I- =  molarity * volume

              = 0.00237 * 1 L 

              = 0.00237 mol

[I-] = moles / total volume
 
    = 0.00237 / 1.625L
   
    = 0.00146 M

moles Pb2+ = molarity * volume 

                     = 0.00785 * 0.625 L

                    = 0.0049 mol 
  
[Pb2+] = 0.0049 / 1.625L

           =  0.003 M 


when        PbI2(s)  ↔     Pb2+(aq)  +  2I-(aq)


when Q = [Pb2+][I-]^2    and we neglect [PbI2] as it is solid

 ∴ Q = 0.003  * (0.00146)^2

        = 6.4 x 10^-9

by comparing the value of Q with Ksp value  we will found that:

Q < Ksp which mean that more solid will dissolve, and this is an unsaturated solution which has ion concentrations < equilibrium concentrations, so the reaction will go forward until achieving equilibrium.
5 0
4 years ago
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