The answer would be: C. 160.3 J/mol*K
To solve this question, you need to know the equation for Gibbs free energy formula. Entropy is expressed as delta S. The temperature would be expressed as T. Don't forget that temperature use Kelvin as unit, not Celsius
The formula would be:
G= H- T*S
130.5 kJ/mol= 178.3kJ/mol - (25+273.15K)*S
(298.15K)*S=178.3kJ/mol - 130.5 kJ/mol
S= (47.8kJ/mol)/ 298.15K=
S= 0.1603 kJ/mol*K= 160.3 J/mol*K ------> 1kJ= 1000J
Answer:
P=681.07mmHg
Explanation:
gas law:
(V1 * P1 ) / T1 = (V2 * P2 ) / T2
⇒ P2 = ( V1 * P1 * T2) / ( T1 * V2)
∴ V1 = 4.6L;
P1 = 365mmHg * 0.001315 atm / 1 mmHg = 0.48 atm
T2 = 36°C + 273 = 309 K
T1 = 20 °C + 273 = 293 K
V2 = 2.6 L
⇒ P2 = ((4.6 L) * (0.48 atm) * (309 K)) / ((293 K) * (2.6 L))
⇒P2 = 0.895 atm ( 681.07 mmHg)
when compressing the gas inside the cylinder, the internal pressure increases
Answer:
5118.50 J
Explanation:
pΔv=nRΔT ;
therefore, ΔT=PV/nR
ΔT = (6.4×10^5)(3.2×10^(-3)/1×8.314
ΔT= 2.4633×10^2 = 246.33 K
specific heat at constant pressure is given as:
c_p = 3/2R
c_p = 12.5 J/mol K
Now, substitute in equation (1)
we know that
Q=ΔU+W ;
and
W=pΔV= 6.4×10^5×3.2×10^(-3) = 2048 J
now
ΔU=CvΔT = 12.465×246.33 =3070.50 J ;
therefore
Q=3070.50+2048= 5118.50 J
Answer:
A
B
C
Explanation:
Remark
Delta H is put on the reactant side of the equation. If delta H is plus the reaction goes to the right. If anything causes delta H to decrease, the reaction shifts left when delta H is originally negative.
One
Delta H is positive which means that heat has to be added before the reaction can take place. If the temperature decreases, then H2 will decrease because delta H is fighting off the temperature decrease The answer is A
Two
Pressure decreases. The side (left or right) with the most number of moles will be favored. The left side has 2 moles. The right side has 4 moles. The right side is favored. Answer: B
Three
The concentration of NH3 increases. That will increase the products. H2 increases. Answer C