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3 years ago

If anyone could plz help ill really appreciate it

Mathematics

1 answer:

Flura [38]3 years ago

3 0

Answer:

Help with what is it mental help? Or no cause I’ve dealt with that a lot

Step-by-step explanation:

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One-half of a number y is more than 22

Anit [1.1K]

Given that,

$\frac{1}{2}y \ \textgreater \ 22$

$\frac{y}{2} \ \textgreater \ 22$

$y \ \textgreater \ 22*2$

$y \ \textgreater \ 44$

Hence, y is any number greater than 44.

4 0

4 years ago

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F=1.8c+32 the high temperature in a mountain city was 15c what is the high temperature in degrees Fahrenheit

ololo11 [35]

F = (1.8 x 15) +32
F = (27) + 32
F = 59

5 0

3 years ago

What is this?

7nadin3 [17]

Commutative property
Changing the order doesn’t change the result
Example 2+3 = 3+2

6 0

4 years ago

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Find the slope of the line through each pair of points (-18, 13) and (-14, -20) *

BARSIC [14]

Answer:

The answer is

$- \frac{33}{4} \\$

Step-by-step explanation:

The slope of a line given two points can be found by using the formula

$m = \frac{ y_2 - y _ 1}{x_ 2 - x_ 1} \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-18, 13) and (-14, -20)

The slope is

$m = \frac{ - 20 - 13 }{ - 14 - - 18} = \frac{ - 33}{ - 14 + 18} = - \frac{33}{4} \\$

We have the final answer as

$- \frac{33}{4} \\$

Hope this helps you

5 0

3 years ago

Will mark Brainlest please answer. find the value of a,b. <br>,p,q from the equal order pairs

NARA [144]

Step-by-step explanation:

<h3>Question-1:</h3>

by order pair we obtain:

$\displaystyle \begin{cases} \displaystyle 3p = 2p - 1 \dots \dots i\\2q - p = 1 \dots \dots ii\end{cases}$

cancel 2p from the i equation to get a certain value of p:

$\displaystyle \begin{cases} \displaystyle p = - 1 \\2q - p = 1 \end{cases}$

now substitute the value of p to the second equation:

$\displaystyle \begin{cases} \displaystyle p = - 1 \\2q - ( - 1) = 1 \end{cases}$

simplify parentheses:

$\displaystyle \begin{cases} \displaystyle p = - 1 \\2q + 1= 1 \end{cases}$

cancel 1 from both sides:

$\displaystyle \begin{cases} \displaystyle p = - 1 \\2q = 0\end{cases}$

divide both sides by 2:

$\displaystyle \begin{cases} \displaystyle p = - 1 \\q = 0\end{cases}$

<h3>question-2:</h3>

by order pair we obtain:

$\displaystyle \begin{cases} \displaystyle 2x - y= 3 \dots \dots i\\3y= x + y \dots \dots ii\end{cases}$

cancel out y from the second equation:

$\displaystyle \begin{cases} \displaystyle 2x - y= 3 \dots \dots i\\ x = 2y \dots \dots ii\end{cases}$

substitute the value of x to the first equation:

$\displaystyle \begin{cases} \displaystyle 2.2y-y= 3 \\ x = 2y \end{cases}$

simplify:

$\displaystyle \begin{cases} \displaystyle 3y= 3 \\ x = 2y \end{cases}$

divide both sides by 3:

$\displaystyle \begin{cases} \displaystyle y= 1 \\ x = 2y \end{cases}$

substitute the value of y to the second equation which yields:

$\displaystyle \begin{cases} \displaystyle y= 1 \\ x = 2 \end{cases}$

<h3>Question-3:</h3>

by order pair we obtain;

$\displaystyle \begin{cases} \displaystyle 2p + q = 2 \dots \dots i\\3q + 2p = 3 \dots \dots ii\end{cases}$

rearrange:

$\displaystyle \begin{cases} \displaystyle 2p + q = 2 \\2p + 3q= 3 \end{cases}$

subtract and simplify

$\displaystyle \begin{array}{ccc} \displaystyle 2p + q = 2 \\2p + 3q= 3 \\ \hline - 2q = - 1 \\ q = \dfrac{1}{2} \end{array}$

substitute the value of q to the first equation:

$\displaystyle 2.p+ \frac{1}{2} = 2$

make q the subject of the equation:

$\displaystyle p = \frac{3}{4}$

hence,

$\displaystyle q = \frac{1}{2} \\ p = \frac{3}{4}$

3 0

3 years ago

Read 2 more answers