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ad-work [718]
2 years ago
12

Part A: The area of a square is (4x2 + 20x + 25) square units. Determine the length of each side of the square by factoring the

area expression completely. Show your work. (5 points)
Part B: The area of a rectangle is (4x2 − 9y2) square units. Determine the dimensions of the rectangle by factoring the area expression completely. Show your work. (5 points)
Mathematics
1 answer:
Viktor [21]2 years ago
5 0

Answer:

Step-by-step explanation:

4x² + 20x + 25 = (2x)² + 2* 2x *5 + 5²

{Compare with a² + 2ab + b² = (a+ b)²}

                         = (2x + 5)²

                         = (2x +5)*(2x+5)

Side of the square = 2x+ 5

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2x^2=9-3x <br> Find the factors
d1i1m1o1n [39]

Answer:

x = -3, $ \frac{3}{2} $

Step-by-step explanation:

The given quadratic equation is: $ 2x^2 = 9 - 3x $

This can be written as: $ 2x^2 + 3x - 9 = 0 $

To solve a quadratic equation of the form $ ax^2 + bx + c = 0 $ we use the formula:

           $ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} $

Here, a = 2; b = 3; c = - 9

Therefore, the roots of the equation are:

$ x = \frac{- 3 \pm \sqrt{9 - 4(2)(-9)}}{2(2)} $

$ \implies x = \frac{-3 \pm \sqrt{81}}{4} $

$ \implies x = \frac{-3 \pm 9}{4} $

We get two values of 'x', viz.,

x = $ \frac{-3 + 9}{4} $ and $ \frac{- 3 - 9}{4} $

$ \implies x = \frac{6}{4} \hspace{5mm} \& \hspace{5mm} \frac{-12}{4} $

⇒ x = -3, 3/2

Since the factors of the quadratic equation is asked, we write it as:

(x + 3)(x - $ \frac{3}{2} $) = 0

because, if (x - a)(x - b) are the factors of a quadratic equation, then 'a' and 'b' are its roots.

Multiply (x + 3) and (x - $ \frac{3}{2} $ to see that this indeed is the given quadratic equation.

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A domain is an input that you put in an equation(x). A range is an output (y) that is the result of a certain input.

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Help me write this two numbers in words<br> 1,328,800,16<br> 15,802
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3 years ago
Write an expression that is equivalent to (3+14)+27
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Answer:

44

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