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3 years ago

8x^3y^-2z^-4/6x^-1yz^-5

Mathematics

1 answer:

choli [55]3 years ago

8 0

4x^2/3yz^9

Mark brainliest please

Hope this helps you

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$d=3\sqrt{2}\ units$

Step-by-step explanation:

The complete question is

Line L contains points (3, 5) and (7, 9). Points P has coordinates (2, 10). Find the distance from P to L

step 1

Find the equation of the line L contains points (3,5) and (7,9)

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substitute

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step 2

Find the equation of the perpendicular line to the given line L that passes through the point P

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The slope of the given line L is $m=1$

The slope of the line perpendicular to the given line L is

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Find the equation of the line in point slope form

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step 3

Find the intersection point equation A and equation B

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$y=-x+12$ ----> equation B

solve the system by graphing

The intersection point is (5.7)

see the attached figure

step 4

we know that

The distance from point P to the the line L is equal to the distance between the point P and point (5,7)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

(2,10) and (5,7)

substitute

$d=\sqrt{(7-10)^{2}+(5-2)^{2}}$

$d=\sqrt{(-3)^{2}+(3)^{2}}$

$d=\sqrt{18}\ units$

simplify

$d=3\sqrt{2}\ units$

see the attached figure to better understand the problem

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8x^3y^-2z^-4/6x^-1yz^-5​

8x^3y^-2z^-4/6x^-1yz^-5