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patriot [66]
3 years ago
6

The phase(s) of matter that demonstrate fluidity include:

Chemistry
1 answer:
melomori [17]3 years ago
3 0

Liquid and Gas are the phases of matter that demonstrate fluidity.

Explanation:

The phenomenon of easy flow or easy transfer or movement of particles is termed as fluidity. As it is known that matters are basically classified into three types or phases. They are solid, liquid and gases. The solid particles are tightly bonded. In other words, high energy is required to move the atoms in the solid material. But in liquid the atoms are slightly loosely bonded. So they are flow easily. With only the viscous tendency hindering its flow, the liquid phased materials can be termed as fluid. Similarly, the easiest travelling particles are gas particles and so they also have fluidity and they are also termed as fluid. So the phases which are termed under fluid criteria demonstrating fluidity included liquid and gas phase

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What is the electronegativity difference for a bond between potassium and iodine? A. 3.3 B. 4.6 C. 0.4 D. 1.7
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20.1 g of aluminum and 219 g of chlorine gas react until all of the aluminum metal has been converted to AlCl3. The balanced equ
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Answer:

<em>The amount of Cl2 gas left , after the reaction goes to completion is : </em><u><em>139.655 grams</em></u>

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Molar mass : It is the mass in grams present in one mole of the substance.

Moles of the substance is calculated by:

Moles=\frac{Mass}{Molar\ mass}

2Al(s)+3Cl_{2}(g)\leftarrow 2AlCl_{3}(g)

According  to this equation:

2 mole of Al = 3 mole of Cl2 = 2 mole of AlCl3

Molar mass of Al = 27.0 g/mol

Mass of Al = 20.1 gram

Moles of Al present in the reaction :

Moles=\frac{Mass}{Molar\ mass}

Moles=\frac{20.1}{26.98}

Moles of Al = 0.744

Similarly calculate the moles of Cl2

Molar mass of Cl2 = 71.0 g/mol

Mass = 219 gram

Moles=\frac{Mass}{Molar\ mass}

Moles=\frac{219}{70.98}

Moles of Cl2 = 3.08 moles

According to equation,

2 mole of Al reacts with = 3 mole of Cl2

1 moles of Al reacts with = 3/2  mole of Cl2

0.744 moles of Al reacts with = 3/2(0.744) moles of Cl2

= 1.116 moles of Cl2

But actually present Cl2 = 3.08 moles

Hence Al is the limiting reagent , and Cl2 is the excess reagent.

The whole Aluminium Al get consumed during the reaction.

The amount of Cl2 in excess = Total Cl2 - Cl2 consumed

Cl2 in excess = 3.08 - 1.116 = 1.964 moles

<u>Cl2 in grams</u><u> </u>= 1.964 x 70.90 <u>= 139.655 grams</u>

6 0
4 years ago
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