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3 years ago

A pizza store offers 24 different toppings. If 2/3 of these choices are non meat how many options does the store offer

1 answer:

3 0

So if you convert 2/3 to 4/6 and you know that 3/6 is 1/2 and 1/2 of 24 toppings is 12 toppings.
I don’t know how to explain this last part but since 4/6 is greater than 3/6 or 1/2 the answer has to be greater than 12 and 6 goes in to 24, 4 times so every 1/6 is 4 there for 2/3 of the toppings are 16 are meat.

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Solve the inequality p/5 < -3

Tema [17]

Answer:

p < - 15

Step-by-step explanation:

Given

$\frac{p}{5}$ < - 3 ( multiply both sides by 5 to clear the fraction )

p < - 15

8 0

2 years ago

Read 2 more answers

Can someone plz help me solved this problem! I’m giving you 10 points! I need help plz help me! Will mark you as brainiest!

Kobotan [32]

Answer: $2 or $9

Step-by-step explanation:

Revenue (R) = $1800 , x = 1100 - 100p

R = xp

1800 = (1100 - 100p)p substituted x with 1100 - 100p

1800 = 1100p - 100p² distributed p into 1100 - 100p

100p² - 1100p + 1800 = 0 added 100p² & subtracted 1100p on both sides

p² - 11p + 18 = 0 divided both sides by 100

(p - 2) (p - 9) = 0 factored quadratic equation

p = 2 p = 9 applied Zero Product Property to solve for p

6 0

3 years ago

Please help solve for x..

aalyn [17]

Answer:

x = 1 or x = -1

Step-by-step explanation:

Given equation:

$x^{100}-4^x \cdot x^{98}-x^2+4^x=0$

Factor out -1:

$\implies -1(-x^{100}+4^x \cdot x^{98}+x^2-4^x)=0$

Divide both sides by -1:

$\implies -x^{100}+4^x \cdot x^{98}+x^2-4^x=0$

Rearrange the terms:

$\implies 4^x \cdot x^{98}-4^x-x^{100}+x^2=0$

$\textsf{Apply exponent rule} \quad a^{b+c}=a^b \cdot a^c \quad \textsf{to }x^{100}:$

$\implies 4^x \cdot x^{98}-4^x-x^{98}x^2+x^2=0$

Factor the first two terms and the last two terms separately:

$\implies 4^x(x^{98}-1)-x^2(x^{98}-1)=0$

Factor out the common term $(x^{98}-1)$ :

$\implies (4^x-x^2)(x^{98}-1)=0$

Zero Product Property: If a ⋅ b = 0 then either a = 0 or b = 0 (or both).

Using the Zero Product Property, set each factor equal to zero and solve for x (if possible):

$\begin{aligned}x^{98}-1 & = 0 & \quad \textsf{or} \quad \quad4^x-x^2 & = 0 \\x^{98} & =1 & 4^x & = x^2 \\x & = 1, -1 & \textsf{no}& \textsf{ solutions for } x \in \mathbb{R}\end{aligned}$