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3 years ago

Can someone help me fast plz

Mathematics

2 answers:

Murljashka [212]3 years ago

7 0

Answer:

That looks confusing

Step-by-step explanation:

Svetradugi [14.3K]3 years ago

4 0

Hi!

All the angles on the blue line are equal 180 degrees. The angle between 7x and 5x is 20 degrees, it is the same as the one on the other side. Knowing that:

20 + 7x + 90 = 180

7x = 70

x = 10

All the angles on the green line are equal 180 degrees, so:

7x + 20 + 5x + 2y = 180

2y = 180 - 20 - 50 - 70

2y = 40

y = 20

Hope this helps!

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Out of seniors at a local high school, 60% went on the senior trip. At the hotel , one room was reserved for every 4 students .

sweet [91]

Answer:

<u>Number of rooms reserved for the students are - 90 .</u>

Step-by-step explanation:

Firstly ,

As we know 60% of the 600 students went on the trip,

Then ,

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= $\frac{60}{100}\times600$

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3 years ago

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3 years ago

The Pew Research Center reported that 73% of Americans who own a cell phone also use text messaging. In a recent local survey, 1

AnnZ [28]

Answer:

$z=\frac{0.775 -0.73}{\sqrt{\frac{0.73(1-0.73)}{200}}}=1.433$

Now we can find the p value. Since we have a bilateral test the p value would be:

$p_v =2*P(z>1.433)=0.152$

Since the p value is higher than the significance level of 0.1 we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

Do Not reject H0

Step-by-step explanation:

Information provided

n=200 represent the sample size slected

X=155 represent the cell phone owners used text messaging

$\hat p=\frac{155}{200}=0.775$ estimated proportion of cell phone owners used text messaging

$p_o=0.73$ is the value to verify

$\alpha=0.1$ represent the significance level

We need to conduct a z test for a proportion

z would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to verify if the true proportion of cell phone owners used text messaging is different from 0.73 so then the system of hypothesis are:

Null hypothesis: $p=0.73$

Alternative hypothesis: $p \neq 0.73$

The statistic to check this hypothesis is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the data given we got:

$z=\frac{0.775 -0.73}{\sqrt{\frac{0.73(1-0.73)}{200}}}=1.433$

Now we can find the p value. Since we have a bilateral test the p value would be:

$p_v =2*P(z>1.433)=0.152$

Since the p value is higher than the significance level of 0.1 we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

Do Not reject H0

6 0

3 years ago