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Blababa [14]
2 years ago
11

HELP ASAP!!!! Use the steps from the experiment to complete this model explaining how the cabbage transferred genetic material f

rom the parent to the offspring.

Chemistry
1 answer:
rodikova [14]2 years ago
6 0

mujhe lagata hai ki aapane kindargartan question post kar diya hai !! is it ??

voh cabbage hai lol !!

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likoan [24]

Answer:

I think is the last one!!!! punnet square ⬜

5 0
3 years ago
Actuary Tong has to study for two actuarial exams: Exam P and Exam FM. The amount of study time that Actuary Tong will spend on
Georgia [21]

The Probability of spending at least half an hour on exactly one subject is mathematically given as

P(1)= 0.50

<h3>What is the Probability of spending at least half an hour on exactly one  subject </h3>

Question Parameters:

The amount of study time that Actuary Tong will spend on each exam in a day follows a continuous random variable that ranges from 0 to 1 hour.

Generally, the equation for the Probability of spending at least half an hour on a subject is mathematically given as

P(A)= (1 – 0.5)/(1 – 0)

P(A)= 0.5

Hence, the Probability of spending at least half an hour on exactly one subject is mathematically given as

P(1)=2​​​​​​C1 * 0.5 * 0.5

P(1)= 0.50

For more information on Probability

brainly.com/question/795909

6 0
3 years ago
Here is a food chain. Use this food to chain to answer this question.
JulijaS [17]
A carnivore is something that eats meat so C. spider would be a Carnivore 
Hope i helped :)
8 0
3 years ago
Read 2 more answers
Two bulbs are connected by a stopcock. The large bulb, with a volume of 6.00 L, contains nitric oxide at a pressure of 0.700 atm
ivolga24 [154]

Answer:

O_{2} and NO_{2}

Explanation:

For a given system at constant temperature, the number of moles of gas present in the system is proportional to the product of the system pressure and volume. Therefore, we have:

NO: 6 L * 0.7 atm = 4.2 L*atm

O:  1.5 L* 2.5 atm = 3.75 L*atm

For the given system based on a balanced chemical equation:

2.70 L*atm of nitric oxide reacts with (2.7/2) 1.35 L*atm of oxygen. This shows that there is more oxygen gas in the system than nitric oxide. Thus nitric oxide is the limiting reactant.

At the end of the experiment:

All the nitirc oxide has been used up, i.e. P_{NO} = 0

For the product: 2.70 L*atm NO produced  2.70 L*atm NO_{2}

The total volume of the system after the stopcock is opened = 6+1.5 = 7.5 L

The partial pressure of NO_{2}  = (2.70 L*atm NO_{2} ) / (7.5 L) = 0.36 atm NO_{2}  

Similarly for oxygen gas:

3.75 L*atm - 1.35 L*atm  = 2.40 L*atm oxygen gas remaining  

Partial pressure of oxygen is:

2.40 L*atm / 7.5 L = 0.32 atm  

Thus, the gases present at the end of the experiment are O_{2} and NO_{2}

3 0
4 years ago
The percent yield for a chemical reaction can not be calculated until the reaction is completed
maw [93]

Answer:

False

Explanation:

using the measurements of the amounts of chemicals, it can be calculated to some degree of accuracy depending mainly on the accuracy of the measurements and enviroments of the reaction

5 0
4 years ago
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