For a (unbalanced) reaction: NaOH +CO2-Na2CO3 + H2O, the moles of NaOH and moles of each product are formed are mathematically given as
a) Moles of NaOH =44.05
b) Moles of Na2CO3=21.0
<h3>What is the moles of NaOH and what moles of each product are formed?</h3>
Generally, the equation for the Chemical reaction is mathematically given as
2 NaOH(aq)+ CO2(g)------> Na2CO3(aq)+ H2O(l)
Therefore
Moles of CO2= 925/44
Moles of CO2=21.0
Hence
Moles of NaOH = 2 x Moles of CO2
Moles of NaOH = 2x925/44
Moles of NaOH =44.05
In conclusion
Moles of Na2CO3 925/44
Moles of Na2CO3=21.0
And
Moles of H2O= 925/44
Moles of H2O= 21.0
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brainly.com/question/16416932
There are 6 atoms because so2, which is sulfur dioxide, has a total of 3 subscripts that is multiplied by 2 because of the coefficient in front of so2.
You know if it's endothermic or exothermic by doing the enthalpy reaction. If the change of temperature is negative then it is exothermic, while positive is endothermic.
If you get -22K then its exothermic, but if you get +22 its endothermic.
A: gold 19.32 g/ml
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Answer:
1=4
2=2
3=hydrogen bonding
4=SO2 is reduced to Sulphur
Explanation:
<h2>I am trying my best okay.</h2>
