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Vilka [71]
3 years ago
6

Tyler says there are indefinitely many additional numbers between 0 and 1 do you agree

Mathematics
2 answers:
Tresset [83]3 years ago
8 0

Answer:

Yes

Step-by-step explanation:

There are infinite numbers between  0 and 1. Think of decimals. E.g.

1.1 , 1.2 , 1.3 , 1.31 , 1.32 , 1.30000000000000009

It goes on forever and never ends. So yes, Tyler is correct.

lawyer [7]3 years ago
7 0

Answer:

yeah like 0.000000000000000000000000000000000000000000000001

Step-by-step explanation:

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Select the correct product. (x + 8)(y + 3) xy + 8x + 3y + 24 xy + 3x + 8y + 24 11xy 24xy
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Is my answer correct or no? <br> ---&gt; show explanation &amp; details if i am wrong!!!
neonofarm [45]

Answer:

No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle ⇒ 3rd answer

Step-by-step explanation:

From the graph of the circle

∵ The center of the circle F is at the origin

∴ F is (0 , 0)

∵ The circle passes through point (7 , 0)

- The length of the radius of the circle is the distance between

   the center of the circle and a point on the circle

∴ r is the distance between points (0 , 0) and (7 , 0)

∴ r=\sqrt{(7-0)^{2}+(0-0)^{2}}=\sqrt{49}=7

∴ The length of the radius of the circle is 7 units

Let us find the distance between point (7 , -7) and the origin (0 , 0)

  • If the distance is equal to the radius of the circle, then the point is on the circle
  • If the distance is greater than the radius, then the point is outside the circle
  • If the distance is less than the radius, then the point is inside the circle

∵ The distance =  \sqrt{(7-0)^{2}+(-7-0)^{2}}=\sqrt{49+49}=\sqrt{98}=7\sqrt{2}

∵ r = 7

∵ 7\sqrt{2} > 7

∴ The distance is greater than the radius of the circle

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The correct answer is:

No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle

<em>Your answer is not correct, the correct answer is the 3rd answer</em>

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