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Ganezh [65]
3 years ago
13

Could a mixture be made up of only elements and no compounds?

Physics
1 answer:
GaryK [48]3 years ago
6 0
A mixture is made of (elements).
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During the first 5 seconds of a rocket launch, the momentum of the rocket increased by 10,000 kg m/s. What was the impulse appli
Pavel [41]

Answer:

10,000 kg m/s

Explanation:

The impulse exerted on an object is equal to the change in momentum of the object itself:

I=F \Delta t = \Delta p

where

I is the impulse

F is the force applied

\Delta t is the time during which the force has been applied

\Delta p is the change in momentum

In this problem, we are already given the change in momentum of the rocket: since the rocket starts from rest, its change in momentum is equal to its momentum after 5 seconds,

\Delta p = 10,000 kg m/s

and so, the impulse is equal to this value.


7 0
3 years ago
What is the method of charging called?
lapo4ka [179]
The answer is conduction
3 0
3 years ago
Read 2 more answers
A bucket filled with water has a mass of 70kg and is hanging from a rope that is wound around a 0.054 m radius stationary cylind
guajiro [1.7K]

Answer:

T = 37.08 [N*m]

Explanation:

We must remember that torque is defined as the product of a force by a distance. This distance is measured from the point of application of force to the center of rotation of the rotating body.

The force is equal to the product of mass by gravitational acceleration.

F=m*g\\F=70*9.81\\F=686.7[N]

Now the torque can be calculated:

T=F*r\\T=686.7*0.054\\T=37.08[N*m]

3 0
3 years ago
A satellite is launched to orbit the Earth at an altitude of 3.25 107 m for use in the Global Positioning System (GPS). Take the
Korolek [52]

Answer:Orbital period =21.22hrs

Explanation:

given that

mass of earth M = 5.97 x 10^24 kg

radius of a satellite's orbit, R=  earth's radius + height of the satellite

6.38X 10^6 +  3.25 X10^7 m =3.89 X 10^7m

Speed of satellite, v= \sqrt GM/R

where G = 6.673 x 10-11 N m2/kg2

V= \sqrt (6.673x10^-11 x 5.97x10^ 24)/(3.89 X 10^ 7m)

V =10,241082.2

v= 3,200.2m/s

a) Orbital period

\sqrt GM/R = \frac{2\pi r}{T}

V= \frac{2\pi r}{T}

T= 2 \pi r/ V

= 2 X 3.142 X 3.89 X 10^7m/ 3,200.2m/s

=76,385.1 s

60 sec= 1min

60mins = 1hr

76,385.1s =hr

76,385.1/3600=21.22hrs

3 0
3 years ago
You are working as an expert witness for an attorney who is suing a shipping company. The company operates ships that carry crud
AnnZ [28]

Answer:

56.7 m³

Explanation:

The radius of the circular area covered by the spill is 4.25 km

You can find the area covered by the spill by applying the formula for area of a circular surface

A=π×r² where π=3.14 and r=4.25km

A= 3.14×4.25² = 56.72 km²

Remember the total area is on average at 1 micron (1μm) thick.This is to say

1μm=1m³

So the minimum volume of oil covering the ocean surface in meters will be;

Change km² to m²

56.72 km²= 56.72×1000000=5.67×10⁷ m²

Finding the volume;

Volume = Area * thickness

Volume= 5.67×10⁷ m² * 1× 10⁻⁶ = 56.7 m³

Minimum amount of oil that was spilled is 56.7 m³

3 0
3 years ago
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