Answer:
10,000 kg m/s
Explanation:
The impulse exerted on an object is equal to the change in momentum of the object itself:

where
I is the impulse
F is the force applied
is the time during which the force has been applied
is the change in momentum
In this problem, we are already given the change in momentum of the rocket: since the rocket starts from rest, its change in momentum is equal to its momentum after 5 seconds,

and so, the impulse is equal to this value.
Answer:
T = 37.08 [N*m]
Explanation:
We must remember that torque is defined as the product of a force by a distance. This distance is measured from the point of application of force to the center of rotation of the rotating body.
The force is equal to the product of mass by gravitational acceleration.
![F=m*g\\F=70*9.81\\F=686.7[N]](https://tex.z-dn.net/?f=F%3Dm%2Ag%5C%5CF%3D70%2A9.81%5C%5CF%3D686.7%5BN%5D)
Now the torque can be calculated:
![T=F*r\\T=686.7*0.054\\T=37.08[N*m]](https://tex.z-dn.net/?f=T%3DF%2Ar%5C%5CT%3D686.7%2A0.054%5C%5CT%3D37.08%5BN%2Am%5D)
Answer:Orbital period =21.22hrs
Explanation:
given that
mass of earth M = 5.97 x 10^24 kg
radius of a satellite's orbit, R= earth's radius + height of the satellite
6.38X 10^6 + 3.25 X10^7 m =3.89 X 10^7m
Speed of satellite, v= 
where G = 6.673 x 10-11 N m2/kg2
V= \sqrt (6.673x10^-11 x 5.97x10^ 24)/(3.89 X 10^ 7m)
V =10,241082.2
v= 3,200.2m/s
a) Orbital period
= 
V= 
T= 2
r/ V
= 2 X 3.142 X 3.89 X 10^7m/ 3,200.2m/s
=76,385.1 s
60 sec= 1min
60mins = 1hr
76,385.1s =hr
76,385.1/3600=21.22hrs
Answer:
56.7 m³
Explanation:
The radius of the circular area covered by the spill is 4.25 km
You can find the area covered by the spill by applying the formula for area of a circular surface
A=π×r² where π=3.14 and r=4.25km
A= 3.14×4.25² = 56.72 km²
Remember the total area is on average at 1 micron (1μm) thick.This is to say
1μm=1m³
So the minimum volume of oil covering the ocean surface in meters will be;
Change km² to m²
56.72 km²= 56.72×1000000=5.67×10⁷ m²
Finding the volume;
Volume = Area * thickness
Volume= 5.67×10⁷ m² * 1× 10⁻⁶ = 56.7 m³
Minimum amount of oil that was spilled is 56.7 m³