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Vanyuwa [196]
2 years ago
7

A heat pump absorbs heat from the atmosphere at a rate of 30 kW. If work is being done to run this heat pump at a rate of 7.7 kW

, what is the coefficient of performance (COP) of the heat pump?A) 2.9B) 22C) 0.26D) 3.9E) 4.9
Physics
1 answer:
Volgvan2 years ago
8 0

Answer:

Option D 3.9

Explanation:

First, you need to use the correct equation which is the following:

COP = Q/W

Where:

Q = heat absorbed

W = work done by the pump

COP = coefficient of perfomance

We have all the data, so, all you need to do is replace in the above expression and you shoould get the correct result:

COP = 30 / 7.7

COP = 3.896

This result you can round it to 3.9. option D.

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Answer:

1.53seconds

Explanation:

Using first equation of motion :

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time(s)=?

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+8.3^2 = +4.4 + 0.65 * t

Making t the subject of the formula :

Therefore, t= ( +8.3 - 4.4)/0.65 = 1.53seconds

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A filing cabinet weighing 556 N rests on the floor. The coefficient of static friction between it and the floor is 0.68, and the
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Explanation:

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A 1.0-kg block of aluminum is at a temperature of 50 Celsius. How much thermal energy will it lose when it’s temperature is redu
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Answer:

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Explanation:

Given data,

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The change in temperature, ΔT = 50° C - 25° C

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The formula for thermal energy,

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