Hello!
I believe its A. wrist flexors but im not exactly sure because it might be B. wrist extensors.
Answer:
the magnitude of the force that the wire will experience = 1.8 N
Explanation:
The force on a current carrying wire placed in a magnetic field is :
F = Idl × B
where:
I = current flowing through the wire
dl = length of the wire
B = magnetic field
We can equally say that :

where : sin θ is the angle at which the orientation from the magnetic field to the wire occurs = 30°
Then;

Given that:
L = 20 cm = 0.2 m
I = 6 A
B = 3 T
θ = 30°
Then:
F = 3 × 6 × 0.2 sin 30°
F = 1.8 N
Therefore, the magnitude of the force that the wire will experience = 1.8 N
I think its true. hope this helps.
A mass weighing 32 pounds stretches a spring 2 feet.
(a) Determine the amplitude and period of motion if the mass is initially released from a point 1 foot above the equilibrium position with an upward velocity of 6 ft/s.
(b) How many complete cycles will the mass have completed at the end of 4 seconds?
Answer:

Period =
seconds
8 cycles
Explanation:
A mass weighing 32 pounds stretches a spring 2 feet;
it implies that the mass (m) = 
m= 
= 1 slug
Also from Hooke's Law
2 k = 32
k = 
k = 16 lb/ft
Using the function:

(because of the initial position being above the equilibrium position)
( as a result of upward velocity)
NOW, we have:

However;
means

also implies that:


Hence, 





Period can be calculated as follows:
= 
=
seconds
How many complete cycles will the mass have completed at the end of 4 seconds?
At the end of 4 seconds, we have:


cycles
Answer:
The acceleration motorcycle
a = 5.13 m / s²
Explanation:
Now to determine the acceleration of the motorcycle
Use the force to analysis motion
∑ F = m * a
∑ F = E - D - m*g * sin ( β ) = m * a
E = 3168 N
D = 230 N
β = 31.6 °
3168 N - 230 N - 286 kg * 9.8 m / s² * sin ( 31.6° ) = 286 kg * a
Now solve to a'
a = [ 3168 N - 230 N - 286 kg * 9.8 m / s² * sin ( 31.6° ) ] / (286 kg)
a = 5.13 m / s²