Answer:
The balanced half-reaction for the reduction of dichromate ion to chromium ion in acidic aqueous solution:

Explanation:
The reaction :

Balancing of reaction in an acidic medium:
Step 1: Balance the atoms in the reaction:

Step 2: Balance oxygen atom by adding water on the side where no oxygen or less oxygen atom is present;

Step 3: Balance the hydrogen atom by adding hydrogen ions on the side where water is absent:

Step 4: Now balance charge by adding electrons on the side where more positive charge is present

The balanced half-reaction for the reduction of dichromate ion to chromium ion in acidic aqueous solution:

INFORMATION:
Is given that:
- if you have a block of plastic and a block of copper that are the same mass and are placed in the sun for 10 minutes.
And after the 10 minutes copper has a higher temperature.
We must determine the reason.
STEP BY STEP EXPLANATION:
To determine it, we need to know the concept of specific heat
If the block of copper has a higher temperature after 10 minutes, that means copper needs less heat to raise its temperature.
So, plastic has a higher specific heat than metal, so it takes more energy to heat plastic than copper. As a result, plastic would heat up more slowly.
ANSWER:
The explanation for the copper having a higher temperature after 10 minutes in the sun, is that plastic has a higher specific heat than metal, so it takes more energy to heat plastic than copper. As a result, plastic would heat up more slowly. Since the copper has a lower specific heat, it will be heat quickly.
Answer:
21.2 grams CH2Cl2
Explanation:
Number of moles: .25
Molar mass of CH2Cl2: 84.93 g/mol
Mass in grams: 84.93(0.250) = 21.2325
Ok first, we have to create a balanced equation for the dissolution of nitrous acid.
HNO2 <-> H(+) + NO2(-)
Next, create an ICE table
HNO2 <--> H+ NO2-
[]i 0.230M 0M 0M
Δ[] -x +x +x
[]f 0.230-x x x
Then, using the concentration equation, you get
4.5x10^-4 = [H+][NO2-]/[HNO2]
4.5x10^-4 = x*x / .230 - x
However, because the Ka value for nitrous acid is lower than 10^-3, we can assume the amount it dissociates is negligable,
assume 0.230-x ≈ 0.230
4.5x10^-4 = x^2/0.230
Then, we solve for x by first multiplying both sides by 0.230 and then taking the square root of both sides.
We get the final concentrations of [H+] and [NO2-] to be x, which equals 0.01M.
Then to find percent dissociation, you do final concentration/initial concentration.
0.01M/0.230M = .0434 or
≈4.34% dissociation.
Answer:
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Explanation: