This problem is asking for the consumption of silver ions when silver nitrate is reacted with copper. In such a case, since no masses are given, we can use the following from similar problems:
Mass of empty beaker: 110.000 g
Mass of beaker with silver nitrate (after all additions) and copper: 331.634 g.
Mass of beaker with silver: 113.395 g.
This means we can write the following chemical equation:
And thus calculate the mass of silver nitrate that will produce the following mass of silver:
Next, we use the 2:2 mole ratio of silver to silver nitrate (silver ions source):
The step will be defined for the given mass of available silver nitrate which will be compared to 5.35 g (consumed mass) to see if they are the same (all consumed) or different (partial consumption).
Learn more:
To solve the concentration, it is equal to the mass of the calcium ions divided by the total mass of the solution.
C = mass of ions / mass solution
C = ( 8.5 x 10 ^-3 g ) / 490 g
C = 1.7 x 10^-5
since the choices are in ppm, multiply it by 10^6
C = (1.7 x 10^-5 ) 10^6
C = 17 ppm
Answer:
The answer to your question is d. Li₂SO₄
Explanation:
Data
H₂SO₄ reacts with LiOH
Process
This is a neutralization reaction that occurs between an acid and a base and the products will always be water and a binary or ternary salt.
In this reaction, the acid is H₂SO₄ and the base is LiOH, then the products will be water and Lithium sulfate.
Balanced chemical reaction
H₂SO₄ + LiOH ⇒ Li₂SO₄ + H₂O
Answer:
its molecular formula must be C10H16O with 2 rings.
Explanation:
the number of rings of the camphor has to be calculated, we have M + = 152.12 in the mass spectrum and it has three double bonds and one ring. The base beak has great abundance.
Since camphor is a single ketone, and M+/MC = 12 ~~ 8, its molecular formula must be C10H16O, accordingly, the number of rings = (10 * 2-16)/2 = 2.
<span>Although the nucleus of an atom is very important, it is the electrons of the atom that determine its chemical properties.
Number of electrons of an atoms (the number of electrons in the outermost level mostly) determine the type of the element (whether it is a metal, metalloid or non-metal).
Based on this, the types of bonds that the atom can form (whether ionic or covalent) is determined, the type of reactions that the element can form is known and the elements that can react with it are also know.</span>
