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dsp73
2 years ago
15

How many grmas of CaCO3 are present in a sample if there are 4. 52 x 10^24 atoms of carbon in that sample?

Chemistry
1 answer:
lorasvet [3.4K]2 years ago
3 0

No of atoms in 1 mol of CaCO3=6.023×10^23

\\ \sf\bull\longmapsto No\:of\:moles=\dfrac{4.52\times 10^24}{6.023\times 10^23}

\\ \sf\bull\longmapsto No\:of\:moles=0.7mol

Molar mass of CaCO3

\\ \sf\bull\longmapsto 40u+12u+3(16u)

\\ \sf\bull\longmapsto 52u+48u

\\ \sf\bull\longmapsto 100g/mol

Now

\\ \sf\bull\longmapsto No\:of\;moles=\dfrac{Given\:Mass}{Molar\:Mass}

\\ \sf\bull\longmapsto Given\:mass=No\:of\:moles\times Molar\:Mass

\\ \sf\bull\longmapsto Given\:Mass=0.7(100)

\\ \sf\bull\longmapsto Given\:Mass=70g

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3 0
2 years ago
Helium gas in a cylinder is under 1.12atm pressure at 25.0C. What will be the pressure if the temperature increases to 37.0C?
Irina18 [472]

Answer:

p_2=1.17atm

Explanation:

Hello!

In this case, considering that the Gay-Lussac's law allows us to relate the temperature-pressure problems as directly proportional relationships:

\frac{p_2}{T_2} =\frac{p_1}{T_1} \\\\

Thus, for the initial pressure and temperature in kelvins the final temperature in kelvins, we compute the final pressure as:

p_2=\frac{p_1T_2}{T_1} \\\\p_2=\frac{1.12atm*310.15K}{298.15K}\\\\p_2=1.17atm

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4 0
2 years ago
For the following reaction, the equilibrium constant Kc is 0.80 at a certain temperature. If the concentration of NO(g) and NOBr
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Answer:

[Br₂] =  1.25M

Explanation:

        2NO (g)  +  Br₂ (g)   ⇄   2NOBr (g)

Eq    0.80M            ?                0.80M

That's the situation told, in the statement.

Let's make the expression for Kc

Kc = [NOBr]² / [Br₂] . [NO]²

Kc = 0.80² / [Br₂] . [0.80]²

0.80 = 1 / [Br₂]

[Br₂] = 1 / 0.80 → 1.25

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3 years ago
AL2(SO4)2.XH2O has 8.1% aluminium by mass.The value of X ?
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Answer:

jgutxutututrxxtdr

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2 years ago
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