The vector ab has a magnitude of 20 units and is parallel to the
vector 4i + 3j. Hence, The vector AB is 16i + 12j.
<h3>How to find the vector?</h3>
If we have given a vector v of initial point A and terminal point B
v = ai + bj
then the components form as;
AB = xi + yj
Here, xi and yj are the components of the vector.
Given;
The vector ab has a magnitude of 20 units and is parallel to the
vector 4i + 3j.
magnitude

Unit vector in direction of resultant = (4i + 3j) / 5
Vector of magnitude 20 unit in direction of the resultant
= 20 x (4i + 3j) / 5
= 4 x (4i + 3j)
= 16i + 12j
Hence, The vector AB is 16i + 12j.
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Answer:
Based on the situation above and the choices provided the he coordinates of S should be (2,4) while the coordinates of R is (-1, 1), and for the T it should be (–3, 3). I hope the answer will help.
Both cyclist are moving apart at a speed of 9.434 mi/hr.
<h3>
What is velocity?</h3>
Velocity is the direction at which an item is moving and serves as a measure of the rate at which its location is changing as seen from a certain point of view and as measured by a specific unit of time (for example, 60 km/h northbound). In kinematics, the area of classical mechanics that deals with the motion of bodies, velocity is a basic idea. A physical vector quantity called velocity must have both a magnitude and a direction in order to be defined. Speed is the scalar absolute value (magnitude) of velocity; it is a coherent derived unit whose quantity is measured in metres per second (m/s or m/s1) in the SI (metric system).
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Answer:
≈ 268 or 85.3π
Step-by-step explanation:
V = 1/3πr²h
V = 1/3 x 3.14 x 4² x 16
V ≈ 267.9467 or 268
also can be considered 85.3π
Answer:
The correct option is option (3) 4 ÷ 25.
Step-by-step explanation:
The expression in terms of <em>m</em> and <em>n</em> is:
![F(m,n)=[\frac{2m^{-1}n^{5}}{3m^{0}n^{4}}]^{2}](https://tex.z-dn.net/?f=F%28m%2Cn%29%3D%5B%5Cfrac%7B2m%5E%7B-1%7Dn%5E%7B5%7D%7D%7B3m%5E%7B0%7Dn%5E%7B4%7D%7D%5D%5E%7B2%7D)
Exponent rule of division:

Compute the value of the expression for <em>m</em> = -5 and <em>n</em> = 3 as follows:
![F(m,n)=[\frac{2m^{-1}n^{5}}{3m^{0}n^{4}}]^{2}](https://tex.z-dn.net/?f=F%28m%2Cn%29%3D%5B%5Cfrac%7B2m%5E%7B-1%7Dn%5E%7B5%7D%7D%7B3m%5E%7B0%7Dn%5E%7B4%7D%7D%5D%5E%7B2%7D)
![F(-5,3)=[\frac{2\csdot (-5)^{-1}\cdot (3)^{5}}{3\cdot (-5)^{0}\cdot (3)^{4}}]^{2}](https://tex.z-dn.net/?f=F%28-5%2C3%29%3D%5B%5Cfrac%7B2%5Ccsdot%20%28-5%29%5E%7B-1%7D%5Ccdot%20%283%29%5E%7B5%7D%7D%7B3%5Ccdot%20%28-5%29%5E%7B0%7D%5Ccdot%20%283%29%5E%7B4%7D%7D%5D%5E%7B2%7D)
![=\{\frac{2}{3}\times [(-5)^{-1-0}\times (3)^{5-4}}]\}^{2}\\\\=\{\frac{2}{3}\times \frac{-1}{5}\times 3\}^{2}\\\\=\{-\frac{2}{5}\}^{2}\\\\=\frac{4}{25}](https://tex.z-dn.net/?f=%3D%5C%7B%5Cfrac%7B2%7D%7B3%7D%5Ctimes%20%5B%28-5%29%5E%7B-1-0%7D%5Ctimes%20%283%29%5E%7B5-4%7D%7D%5D%5C%7D%5E%7B2%7D%5C%5C%5C%5C%3D%5C%7B%5Cfrac%7B2%7D%7B3%7D%5Ctimes%20%5Cfrac%7B-1%7D%7B5%7D%5Ctimes%203%5C%7D%5E%7B2%7D%5C%5C%5C%5C%3D%5C%7B-%5Cfrac%7B2%7D%7B5%7D%5C%7D%5E%7B2%7D%5C%5C%5C%5C%3D%5Cfrac%7B4%7D%7B25%7D)
Thus, the correct option is option (3) 4 ÷ 25.