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k0ka [10]
3 years ago
10

What are Integers ~ ​

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
5 0

Answer:

Integers are simply whole valued positive or negative numbers, including 0.

Step-by-step explanation:

A cheerful teen willing to help,

stay positive,

stay salty...

vodomira [7]3 years ago
3 0
Integers are a whole number (not a fractional number) that can be positive, negative, or zero. Examples of integers are: -5, 1, 5, 8
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What is the area of this figure?
coldgirl [10]
Answer: 102

-----------------------------------------------

We'll use the formula 
A = h*(b1+b2)/2
where
A = area of trapezoid
h = height
b1 & b2 are the parallel bases

In this case,
b1 = 6+7 = 13
b2 = 21
h = 6

Making the area to be
A = h*(b1+b2)/2
A = 6*(13+21)/2
A = 6*(34)/2
A = 204/2
A = 102

Side Note: We don't use the slanted side of 10 cm at all

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4 years ago
5x – 6y = –29: ( __, 4)
Xelga [282]
Hola, qué tal tu día
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How many cups are in 4 feet
Oksanka [162]

Answer:

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3 years ago
Read 2 more answers
Simplify x^2 -x-6/4x^3 * 2x^2 +2x/x^2+5x+6 And PLS show work.
Sedbober [7]

To solve this problem you must apply the proccedure shown below:

1. You have the following expression given in the problem above:

( \frac{x^{2}-x-6}{4x^{3}}) (\frac{x^{2}+2x}{x^{2}+5x+6} )

2. First, you must factor the polynomials in the numerator and in the denominator and then simplify the expression:

(\frac{(x-3)(x+2)}{4x^{3}} ) (\frac{2x(x+1)}{(x+3)(x+2)})=\frac{(x-3)(x+1)}{2x^{2}(x+3)(x+2)}

The answer is: \frac{(x-3)(x+1)}{2x^{2}(x+3)(x+2)}

3 0
4 years ago
Can someone answer 7-11 for me by 12:00AM
lawyer [7]

Answer:

Step-by-step explanation:

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x(4 - x) = - 96 ⇔ x² - 4x - 96 = 0

D = ( - 4)² - 4(1)(- 96) = 400 = (20)²

x_{1} = (- ( - 4) - 20) ÷ 2(1) = - 8

x_{2} = ( - ( - 4) + 20) ÷ 2 = 12

Numbers are <em>- 8</em> and <em>12</em>

<em>8).</em> <em><u>It's your turn now. You can do it</u></em>

<em>9).</em> x² - 5x + 3 = 0

0 < x_{1} < 1

4 < x_{2} < 5

<em>10).</em> - x² + 3x + 1 = 0

-1 < x_{1} < 0

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- 3 < x_{1} < - 2

0 < x_{2} < 1

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3 years ago
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